Chapter 11, Problem 11.5P

Interpretation Introduction

Interpretation:

The vapor pressure of propane at $25°\text{C}$ is to be calculated.

Concept introduction: The vapor pressure of substance relies upon the boiling point of the substance. It is calculated by the use of Clausius-Clapeyron equation,

$\text{ln}\left(\frac{P_2}{P_1}\right)=-\frac{\Delta H_{\text{vap}}}{\text{R}}\left(\frac{1}{T_2}-\frac{1}{T_1}\right)$

To determine: The vapor pressure of propane at $25°\text{C}$ .