Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN: 9781259696527
Author: J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher: McGraw-Hill Education
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Chapter 11, Problem 11.2P
Interpretation Introduction

Interpretation:

Mixture volume V when 750 cm3 of pure species 1(ethanol) is mixed with 1500 cm3 of species 2 (methyl butyl ether) at 250C and ideal solution volume Vid should be calculated.

Concept Introduction:

Mole fraction x1 and x2 will be calculated first. Mole of a species will be calculated by dividing its total volume by its specific volume. Mole fraction of a species corresponds to its total mole divided by total mole of the mixture.

  ΔV will be calculated next after putting x1 and x2 value in the given expression.

  VE=VxiVi and VE=ΔV

Since ΔV, V1, V2, x1 and x2 are known, V can be calculated. Here V is volume per mol. To calculate total mixture volume, V is to be multiplied with total mole of mixture.

Ideal solution volume of mixture Vid=xiVi . Since, V1, V2, x1 and x2 are known, Vid can be calculated unit of which will be in volume per mol. To calculate total ideal mixture volume, Vid is to be multiplied with total mole of mixture.

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