(a)
Interpretation: The products that are formed by the reaction of the given terminal
Concept introduction: A stepwise procedure of transforming an alkyne into a carbonyl group is known hydroboration-oxidation reaction. In a hydroboration-oxidation reaction, a terminal alkyne reacts with
A terminal alkyne reacts with
(b)
Interpretation: The products that are formed by the reaction of the given terminal alkyne, with [1]
Concept introduction: A stepwise procedure of transforming an alkyne into a carbonyl group is known hydroboration-oxidation reaction. In a hydroboration-oxidation reaction, a terminal alkyne reacts with
A terminal alkyne reacts with
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- Draw the organic products formed when cyclopentene is treated with each reagent. With some reagents, no reaction occurs. a.H2 + Pd-C b.H2 + Lindlar catalyst c.Na, NH3 d.CH3CO3H e.[1] CH3CO3H; [2] H2O, HO− f.[1]OsO4 + NMO; [2] NaHSO3, H2O g.KMnO4, H2O, HO− h.[1] LiAlH4; [2] H2O i. [1] O3; [2] CH3SCH3 j.(CH3)3COOH, Ti[OCH(CH3)2]4, (−)-DET k.mCPBA l.Product in (k); then [1] LiAlH4; [2] H2Oarrow_forwardDraw the constitutional isomer formed when the following alkenes are treated with each set of reagents: [1] H2O, H2SO4; or [2] BH3 followed by H2O2, −OH.arrow_forwardWhen alkyne A is treated with NaNH2 followed by CH3I, a product having molecular formula C6H10O is formed, but it is not compound B. What is the structure of the product, and why is it formed?arrow_forward
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- Ketones and aldehydes react with sodium acetylide (the sodium salt of acetylene) to give alcohols, as shown in the following example: R, OH 1. HC=C: Na* 2. Hзо C. R2 R2 HC Draw the structure of the major reaction product when the following compound reacts with sodium acetylide, assuming that the reaction takes preferentially from the Re face of the carbonyl group. Use the wedge/hash bond tools to indicate stereochemistry where it exists. You do not have to explicitly draw H atoms. If a group is achiral, do not use wedged or hashed bonds on it.arrow_forwardWhich of the following pairs are keto–enol tautomers?arrow_forwardHw.114.arrow_forward