Concept explainers
a)
Interpretation:
The IUPAC name of the
Concept introduction:
The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.
To give:
The IUPAC name of the alkyl halide shown.
Answer to Problem 14VC
The alkyl halide given is
Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.
Explanation of Solution
The compound has a cyclohexane ring with a Cl atom on C1 and a methyl on C3 both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.
The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.
b)
Interpretation:
The IUPAC name of the alkyl halide is to be given.
Concept introduction:
The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.
To give:
The IUPAC name of the alkyl halide shown.
Answer to Problem 14VC
The alkyl halide given is
Its IUPAC name is 4-chloro-2-methyl-2-heptene.
Explanation of Solution
The compound has a seven carbon straight chain with a double bond between C2 & C3, a Cl atom on C4 and a methyl on C3. Hence its name is 4-chloro-2-methyl-2-heptene.
The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.
Want to see more full solutions like this?
Chapter 10 Solutions
Organic Chemistry - With Access (Custom)
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. I I I H Select to Add Arrows HCI, CH3CH2OHarrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and the follow the arrows to draw the intermediate and product in this reaction or mechanistic step(s).arrow_forward
- Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the intermediates and product of the following reaction or mechanistic step(s).arrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the intermediate and the product in this reaction or mechanistic step(s).arrow_forwardLook at the following pairs of structures carefully to identify them as representing a) completely different compounds, b) compounds that are structural isomers of each other, c) compounds that are geometric isomers of each other, d) conformers of the same compound (part of structure rotated around a single bond) or e) the same structure.arrow_forward
- Given 10.0 g of NaOH, what volume of a 0.100 M solution of H2SO4 would be required to exactly react all the NaOH?arrow_forward3.50 g of Li are combined with 3.50 g of N2. What is the maximum mass of Li3N that can be produced? 6 Li + N2 ---> 2 Li3Narrow_forward3.50 g of Li are combined with 3.50 g of N2. What is the maximum mass of Li3N that can be produced? 6 Li + N2 ---> 2 Li3Narrow_forward
- Concentration Trial1 Concentration of iodide solution (mA) 255.8 Concentration of thiosulfate solution (mM) 47.0 Concentration of hydrogen peroxide solution (mM) 110.1 Temperature of iodide solution ('C) 25.0 Volume of iodide solution (1) used (mL) 10.0 Volume of thiosulfate solution (5:03) used (mL) Volume of DI water used (mL) Volume of hydrogen peroxide solution (H₂O₂) used (mL) 1.0 2.5 7.5 Time (s) 16.9 Dark blue Observations Initial concentration of iodide in reaction (mA) Initial concentration of thiosulfate in reaction (mA) Initial concentration of hydrogen peroxide in reaction (mA) Initial Rate (mA's)arrow_forwardDraw the condensed or line-angle structure for an alkene with the formula C5H10. Note: Avoid selecting cis-/trans- isomers in this exercise. Draw two additional condensed or line-angle structures for alkenes with the formula C5H10. Record the name of the isomers in Data Table 1. Repeat steps for 2 cyclic isomers of C5H10arrow_forwardExplain why the following names of the structures are incorrect. CH2CH3 CH3-C=CH-CH2-CH3 a. 2-ethyl-2-pentene CH3 | CH3-CH-CH2-CH=CH2 b. 2-methyl-4-pentenearrow_forward
Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning