Concept explainers
a)
Interpretation:
The IUPAC name of the
Concept introduction:
The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.
To give:
The IUPAC name of the alkyl halide shown.
Answer to Problem 14VC
The alkyl halide given is
Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.
Explanation of Solution
The compound has a cyclohexane ring with a Cl atom on C1 and a methyl on C3 both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.
The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.
b)
Interpretation:
The IUPAC name of the alkyl halide is to be given.
Concept introduction:
The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.
To give:
The IUPAC name of the alkyl halide shown.
Answer to Problem 14VC
The alkyl halide given is
Its IUPAC name is 4-chloro-2-methyl-2-heptene.
Explanation of Solution
The compound has a seven carbon straight chain with a double bond between C2 & C3, a Cl atom on C4 and a methyl on C3. Hence its name is 4-chloro-2-methyl-2-heptene.
The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.
Want to see more full solutions like this?
Chapter 10 Solutions
Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!)
- The following equations represent the formation of compound MX. What is the AH for the electron affinity of X (g)? X₂ (g) → 2X (g) M (s) → M (g) M (g) M (g) + e- AH = 60 kJ/mol AH = 22 kJ/mol X (g) + e-X (g) M* (g) +X (g) → MX (s) AH = 118 kJ/mol AH = ? AH = -190 kJ/mol AH = -100 kJ/mol a) -80 kJ b) -30 kJ c) -20 kJ d) 20 kJ e) 156 kJarrow_forwardA covalent bond is the result of the a) b) c) d) e) overlap of two half-filled s orbitals overlap of a half-filled s orbital and a half-filled p orbital overlap of two half-filled p orbitals along their axes parallel overlap of two half-filled parallel p orbitals all of the abovearrow_forwardCan the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left? starting material target If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area. Be sure you follow the standard ALEKS rules for submitting syntheses. + More... Note for advanced students: you may assume that you are using a large excess of benzene as your starting material. C T Add/Remove step X ноarrow_forward
- Which one of the following atoms should have the largest electron affinity? a) b) c) d) 으으 e) 1s² 2s² 2p6 3s¹ 1s² 2s² 2p5 1s² 2s² 2p 3s² 3p² 1s² 2s 2p 3s² 3p6 4s2 3ds 1s² 2s² 2p6arrow_forwardAll of the following are allowed energy levels except _. a) 3f b) 1s c) 3d d) 5p e) 6sarrow_forwardA student wants to make the following product in good yield from a single transformation step, starting from benzene. Add any organic reagents the student is missing on the left-hand side of the arrow, and any addition reagents that are necessary above or below the arrow. If this product can't be made in good yield with a single transformation step, check the box below the drawing area. Note for advanced students: you may assume that an excess of benzene is used as part of the reaction conditions. : ☐ + I X This product can't be made in a single transformation step.arrow_forward
- Ppplllleeeaaasssseeee helllppp wiithhh thisss Organic chemistryyyyyy I talked like this because AI is very annoyingarrow_forwardName the family to which each organic compound belongs. The first answer has been filled in for you. compound CH₂ || CH3-C-NH2 0 ။ CH3-C-CH₂ CH=O–CH=CH, CH₂ HO CH2-CH2-CH-CH3 family amine Darrow_forward1b. Br LOHarrow_forward
Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning