The hydrogen atom that gets easily abstracted from the given molecule vitamin E should be determined. Concept introduction: Radical or free radical: The unpaired valence electron of an atom, molecule, or ion is called as radical. The stability order for radical is as follows, benzylic > allylic > tertiary > secondary > primary > methyl The movement of single electron present in the molecule is usually denoted by using the half headed arrows called fishhook arrows. Resonance: The molecule is said to have resonance structures if it has more than one structure by migrating lone pair, radical or the phi bonds present in the molecule. Resonance stabilization : Due to the delocalization of electrons within the molecule the overall energy becomes lower and makes the molecule more stable. Bond strength present in the molecule depends on the formation of the radical, if the radical formed is resonance stabilized then the bond associated with it is weak than the other bond present in the molecule.

Question

Want to see the full answer?

Answer 1

Question

Chapter 10.9, Problem 20CC

Interpretation Introduction

Interpretation:

The hydrogen atom that gets easily abstracted from the given molecule vitamin E should be determined.

Concept introduction:

Radical or free radical: The unpaired valence electron of an atom, molecule, or ion is called as radical. The stability order for radical is as follows,

benzylic > allylic > tertiary > secondary > primary > methyl

The movement of single electron present in the molecule is usually denoted by using the half headed arrows called fishhook arrows.

Resonance: The molecule is said to have resonance structures if it has more than one structure by migrating lone pair, radical or the phi bonds present in the molecule.

Resonance stabilization: Due to the delocalization of electrons within the molecule the overall energy becomes lower and makes the molecule more stable.

Bond strength present in the molecule depends on the formation of the radical, if the radical formed is resonance stabilized then the bond associated with it is weak than the other bond present in the molecule.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Part 1. Draw monomer units of the following products and draw their reaction mechanism 1) Bakelite like polymer Using: Resorcinol + NaOH + Formalin 2) Polyester fiber Using a) pthalic anhydride + anhydrous sodium acetate + ethylene glycol B)pthalic anhydride + anhydrous sodium acetate + glycerol 3) Temporary cross-linked polymer Using: 4% polyvinyl alcohol+ methyl red + 4% sodium borate

Using the table of Reactants and Products provided provide the correct letter that corresponds with the Carboxylic acid that is formed in the reaction below. 6 M NaOH Acid-workup WRITE THE CORRECT LETTER ONLY DO NOT WRITE EXTRA WORDS OR PHRASES A) Pool of Reagents for Part B CI B) OH C) E) CI J) racemic F) K) OH N) OH P) G) OH D) HO H) L) M) HO Q) R) CI A

In the table below, the exact chemical structures for Methyl salicylate can be represented by the letter WRITE THE CORRECT LETTER ONLY DO NOT WRITE EXTRA WORDS OR PHRASES CI B) A) E) Cl racemic F) J) CI K) N) OH P) Pool of Reagents for Part B OH OH G) L) OH D) HO H) M) HO Q) R) CI