
The graph of the curve of a parametric equation x=3t2, y=t+1 ; −∞<t<∞, show its orientation. Find the rectangular equation of curve.

Answer to Problem 13AYU
Solution:
The graph of the parametric equations x=3t2, y=t+1 ; −∞<t<∞ is
The rectangular equation of the parametric equation x=3t2, y=t+1 ; −∞<t<∞ is x=3(y−1)2.
Explanation of Solution
Given information:
The parametric equation x=3t2, y=t+1 ; −∞<t<∞
Explanation:
To draw the given parametric equation, plug some values of t in the given equation and find few points on the curve.
The interval for t is −∞<t<∞
tx(t)=3t2y(t)=t+1(x,y)−212−1(12,−1)−130(3,0)001(0,1)132(3,2)3274(27,4)
The orientation is curve traced out in a certain direction by the corresponding succession of points (x,y).
The arrow shows the orientation along the curve as t varies from −∞<t<∞
As t takes values from −∞<t<∞, the corresponding orientation is from (12,−1) to (27,4)
Use points in the table to sketch the curve.
The graph of the parametric equation x=3t2, y=t+1 ; −∞<t<∞ is
Now, let x=3t2 ——- (1)
y=t+1 ——- (2)
Solve equation (2) for variable t,
⇒t=y−1
Substitute this result for t into equation (1),
⇒x=3(y−1)2
The rectangular equation of the parametric equation x=3t2, y=t+1 ; −∞<t<∞ is x=3(y−1)2.
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