Tofind:the equation of conic using its given description and graph the equation.
Answer to Problem 32RE
The hyperbolic equationis
Explanation of Solution
Given:
The hyperbola vertices are
The focus is at
Concept used:
Formula for hyperbola forming open left and right.
Form:
Center=
Vertices=
Slope of asymptotes:
Equation of asymptotes:
Formula for hyperbola opening up and down:
Form:
Center:
Vertices:
Slope of asymptotes:
Calculation:
According to the given:
The hyperbola verticesare
The focus is at
Thus, the equation is in the form:
vertices
Focus=
Thus,
Now,
Hence the equation is
The equation can be in shown in graph as:
The graph of hyperbolic equation
Hence, hyperbolic equation is
Chapter 10 Solutions
Precalculus
Additional Math Textbook Solutions
Glencoe Math Accelerated, Student Edition
Calculus and Its Applications (11th Edition)
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