EBK MECHANICS OF MATERIALS
7th Edition
ISBN: 9780100257061
Author: BEER
Publisher: YUZU
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Textbook Question
Chapter 10.4, Problem 92P
Solve Prob. 10.91 using the interaction method and an allowable stress in bending of 1300 psi.
10.91 A sawn-lumber column of 5.0 × 7.5-in. cross section has an effective length of 8.5 ft. The grade of wood used has an adjusted allowable stress for compression parallel to the grain σC = 1180 psi and an adjusted modulus E = 440 × 103 psi. Using the allowable-stress method, determine the largest eccentric load P that can be applied when (a) e = 0.5 in., (b) e = 1.0 in.
Fig. P10.91
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Formala for Hunzontal component= + cos &
Vertical Component: Fsin t
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30°
200 N
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//
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a₂+b₂
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a = lbl = 2o unite
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11 vector & wt Honzontal Axis - 60°
b
b
a= |a|
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ag = 10
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a
1
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= 10
= 20 Cos 60 = It
by = 161 sin 60 = 20 sia 60 = 17.32
b₁
Rx
ax +bx = 17.32 +10=2732
a₁
a₁+b₁
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By = ou + by=
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45
Chapter 10 Solutions
EBK MECHANICS OF MATERIALS
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