(a)
Interpretation:
The product of stereoisomers that formed in the given reaction should be given.
Concept introduction:
Isomer:
The compound is having same molecular formula but arrangement of the atom is different is called isomer.
In the nucleophilic substitution reaction, the
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergoes
In the nucleophilic substitution reaction, the rate of reaction depends on reactant as well as nucleophile, which are involved in reaction is called bimolecular nucleophilic substitution reaction.
In
Reactant and nucleophile are present at the rate determination step.
The order of species involving in
Tertiary < Secondary < Primary
(b)
Interpretation:
The product of stereoisomers that formed in the given reaction should be given.
Concept introduction:
Isomer:
The compound is having same molecular formula but arrangement of the atom is different is called isomer.
In the nucleophilic substitution reaction, the rate of reaction depends only on one reactant, which is involved in reaction is called unimolecular nucleophilic substitution reaction.
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergoes
In the nucleophilic substitution reaction, the rate of reaction depends on reactant as well as nucleophile, which are involved in reaction is called bimolecular nucleophilic substitution reaction.
In
Reactant and nucleophile are present at the rate determination step.
The order of species involving in
Tertiary < Secondary < Primary
(c)
Interpretation:
The product of stereoisomers that formed in the given reaction should be given.
Concept introduction:
Isomer:
The compound is having same molecular formula but arrangement of the atom is different is called isomer.
In the nucleophilic substitution reaction, the rate of reaction depends only on one reactant, which is involved in reaction is called unimolecular nucleophilic substitution reaction.
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergoes
In the nucleophilic substitution reaction, the rate of reaction depends on reactant as well as nucleophile, which are involved in reaction is called bimolecular nucleophilic substitution reaction.
In
Reactant and nucleophile are present at the rate determination step.
The order of species involving in
Tertiary < Secondary < Primary
(d)
Interpretation:
The product of stereoisomers that formed in the given reaction should be given.
Concept introduction:
Isomer:
The compound is having same molecular formula but arrangement of the atom is different is called isomer.
In the nucleophilic substitution reaction, the rate of reaction depends only on one reactant, which is involved in reaction is called unimolecular nucleophilic substitution reaction.
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergoes
In the nucleophilic substitution reaction, the rate of reaction depends on reactant as well as nucleophile, which are involved in reaction is called bimolecular nucleophilic substitution reaction.
In
Reactant and nucleophile are present at the rate determination step.
The order of species involving in
Tertiary < Secondary < Primary
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Chapter 10 Solutions
CHEM 262 ORG CHEM EBOOK DIGITAL DELIVERY
- I need help working this problem out step by step, I was trying to use my example from the txt book but all I know how to do is set it up. I need to be shown step by step as I am a visual learner. Please help me.arrow_forwardDon't used hand raitingarrow_forwardDon't used Ai solution and don't used hand raitingarrow_forward
- & Calculate the molar enthalpy of combustion (A combH) of 1.80 g of pyruvic acid (CH3COCOOH; 88.1 g mol-1) at 37 °C when they are combusted in a calorimeter at constant volume with a calorimeter constant = 1.62 kJ °C-1 and the temperature rose by 1.55 °C. Given: R = 8.314 J mol −1 °C-1 and the combustion reaction: AN C3H4O3 + 2.502(g) → 3CO2(g) + 2H2O(l)arrow_forwardAn unknown salt, AB, has the following precipitation reaction:A+(aq) + B-(aq) ⇌ AB(s) the K value for this reaction is 4.50 x10-6. Draw a model that represents what will happen when 1.00 L each of 1.00 M solution of A+(aq) and 1.00M solution of B-(aq) are combined.arrow_forward5. a) Use the rules in Example 4.4 (p. 99) and calculate sizes of octahedral and tetrahedral cavities in titanium and in zirconium. Use values for atomic radii given in Fig. 9.1 (p.291). (3 points) b) Consider the formation of carbides (MC) of these metals. Which metal is able to accommodate carbon atoms better, and which cavities (octahedral or tetrahedral) would be better suited to accommodate C atoms into metal's lattice? (4 points)arrow_forward
- 2. Read paragraph 3.4 in your textbook ("Chiral Molecules"), and explain if Cobalt(ethylenediamine) 33+ shown in previous problem is a chiral species. If yes, draw projections of both enantiomers as mirror images, analogous to mirror projections of hands (below). Mirror (4 points)arrow_forward3. Borane (BH3) belongs to D3h point group. Consider the vibrational (stretching) modes possible for B-H bonds under D3h symmetry. Using the methods we used in class, construct the reducible representation I, and break it down into irreducible representations using the character table provided. Sketch those modes, indicate whether they are IR-active. (6 points) D3h E 2C3 3C2 σh 283 30% A₁' 1 1 1 1 1 1 x² + y², z² 1 -1 1 1 -1 R₂ E' 2 0 2 0 (x, y) (x² - y², xy) " A₁" 1 1 -1 A2" 1 -1 -1 1 Z E" 2 -1 0 -2 1 0 (Ry, Ry) (xz, yz)arrow_forward1. List all the symmetry elements, and assign the compounds to proper point groups: a) HCIBrC-BrCIH Cl Br H (2 points) H Br b) Pentacarbonylmanganese(I)bromide Br OEC-Mn-CEO 00- c) Phenazine (aromatic molecule, with delocalized bonding) 1 d) Cobalt(ethylenediamine)33+ (just the cation) 3+ H₂N H₂ .NH2 (CI)3 NH2 H2 H₂N. (2 points) (2 points) (2 points)arrow_forward
- Hello, I desperately need help figuring out 8-14; I also wanted to see if you would mind letting me know if I picked the right degree as my melting points on the two graphs. Please and thank you in advance! All the information is provided.arrow_forwardThe reaction: A + B ⇌ 2 C, can be represented by the equilibrium expression, KC =[C]2[A][B]=258 at 520K.When 1.00 M of C was allowed to reach equilibrium and 0.055 M of A was formed. If this reaction wasperformed at the same temperature using 0.500 M C, what would the equilibrium concentration of Abe?arrow_forward1. What is the functional group of an alcohol and a phenol? 2. Why are some alcohols soluble in water? 3. Classify each of the following alcohols as primary, secondary or tertiary. a. 3-pentanol b. 2-methyl-2-butanol c. 1-propanolarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
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