(a)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
In the nucleophilic substitution reaction, the
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergoes
(b)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
In the nucleophilic substitution reaction, the rate of reaction depends only on one reactant, which is involved in reaction is called unimolecular nucleophilic substitution reaction.
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergoes
(c)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
In the nucleophilic substitution reaction, the rate of reaction depends only on one reactant, which is involved in reaction is called unimolecular nucleophilic substitution reaction.
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergoes
(d)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
In the nucleophilic substitution reaction, the rate of reaction depends only on one reactant, which is involved in reaction is called unimolecular nucleophilic substitution reaction.
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergoes
(e)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
In the nucleophilic substitution reaction, the rate of reaction depends only on one reactant, which is involved in reaction is called unimolecular nucleophilic substitution reaction.
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergoes
(f)
Interpretation:
The major product of the given reaction should be given.
Concept introduction:
In the nucleophilic substitution reaction, the rate of reaction depends only on one reactant, which is involved in reaction is called unimolecular nucleophilic substitution reaction.
In
The rate determination step is formation of carbocation.
The stability order of carbocation is,
Tertiary > Secondary > Primary
Therefore, tertiary alcohols undergo substitution very fast than the secondary alcohols because tertiary carbocation is more stable than the secondary carbocation than the primary carbocation. Primary alcohol is less stable therefore it won’t undergoes
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Chapter 10 Solutions
CHEM 262 ORG CHEM EBOOK DIGITAL DELIVERY
- 2. Read paragraph 3.4 in your textbook ("Chiral Molecules"), and explain if Cobalt(ethylenediamine) 33+ shown in previous problem is a chiral species. If yes, draw projections of both enantiomers as mirror images, analogous to mirror projections of hands (below). Mirror (4 points)arrow_forward3. Borane (BH3) belongs to D3h point group. Consider the vibrational (stretching) modes possible for B-H bonds under D3h symmetry. Using the methods we used in class, construct the reducible representation I, and break it down into irreducible representations using the character table provided. Sketch those modes, indicate whether they are IR-active. (6 points) D3h E 2C3 3C2 σh 283 30% A₁' 1 1 1 1 1 1 x² + y², z² 1 -1 1 1 -1 R₂ E' 2 0 2 0 (x, y) (x² - y², xy) " A₁" 1 1 -1 A2" 1 -1 -1 1 Z E" 2 -1 0 -2 1 0 (Ry, Ry) (xz, yz)arrow_forward1. List all the symmetry elements, and assign the compounds to proper point groups: a) HCIBrC-BrCIH Cl Br H (2 points) H Br b) Pentacarbonylmanganese(I)bromide Br OEC-Mn-CEO 00- c) Phenazine (aromatic molecule, with delocalized bonding) 1 d) Cobalt(ethylenediamine)33+ (just the cation) 3+ H₂N H₂ .NH2 (CI)3 NH2 H2 H₂N. (2 points) (2 points) (2 points)arrow_forward
- Hello, I desperately need help figuring out 8-14; I also wanted to see if you would mind letting me know if I picked the right degree as my melting points on the two graphs. Please and thank you in advance! All the information is provided.arrow_forwardThe reaction: A + B ⇌ 2 C, can be represented by the equilibrium expression, KC =[C]2[A][B]=258 at 520K.When 1.00 M of C was allowed to reach equilibrium and 0.055 M of A was formed. If this reaction wasperformed at the same temperature using 0.500 M C, what would the equilibrium concentration of Abe?arrow_forward1. What is the functional group of an alcohol and a phenol? 2. Why are some alcohols soluble in water? 3. Classify each of the following alcohols as primary, secondary or tertiary. a. 3-pentanol b. 2-methyl-2-butanol c. 1-propanolarrow_forward
- I need help with B2 using the information in B1. This is for my lab notebook, and I got confused on number 2. Please help.arrow_forward4. Aluminum has a face-centered cubic structure. The unit cell length is 4.05Å. Calculate the radius of Al atom in the metal. (5 points).arrow_forwardHF and HNO2 are both considered weak acids. Given the following K values for their dissociationequations, which is the weaker of these two weak acids?HF (aq) ⇌ H+(aq) + F –(aq) K=6.6 x10-4 HNO2 (aq) ⇌ H+(aq) + NO2–(aq) K=7.2 X 10-4arrow_forward
- The equilibrium constant for this reaction is 5.88 x 104. If concentration of the lead ion is 5.24 M, whatis the concentration of the chloride ion?Pb2+(aq) + 2 Cl- (aq) ⇌ PbCl2(s)arrow_forwardc. 1-propanoi 4. If you add chromate, an oxidizing agent, to each of the following, would a green Cr3+ solution be formed? a. 3-pentanol b. 2-methyl-2-butanol c. 1-propanol 5. If an alcohol solution has a pH of 5, would it be a primary alcohol, a secondary alcohol, a tertiary alcohol, or a phenol?arrow_forwardGiven the reaction: A(aq) + B(aq) ⇌ 2C(aq) + D(aq). 2.00 moles of each reactant were dissolved into 1.00 literof water. The reaction reached equilibrium, and at equilibrium the concentration of A was 1.60 M.A) Calculate the equilibrium concentrations for each substance. B) Write the equilibrium constant expression. C) Calculate the value for the equilibrium constant, Keq.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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