In Problems 47 and 48, derive the formulas of Theorem 4 for the solution of any 2 × 2 non strictly determined matrix game by rewriting and analyzing E P , Q = a p 1 q 2 + b p 1 q 2 + c p 2 q 1 + d p 2 q 2 (4) (See the solution of the two-finger Morra game on pages G9-G11.) (A) Let p 2 = 1 − p 1 and q 2 = 1 − q 1 and simplify (4) to show that E P , Q = D p 1 − d − c q 1 + b − d p 1 + d where D = a + d − b + c . (B) Show that if p 1 is chosen so that D p 1 − d − c = 0 , then v = a d − b c D , regardless of the value of p 1 .
In Problems 47 and 48, derive the formulas of Theorem 4 for the solution of any 2 × 2 non strictly determined matrix game by rewriting and analyzing E P , Q = a p 1 q 2 + b p 1 q 2 + c p 2 q 1 + d p 2 q 2 (4) (See the solution of the two-finger Morra game on pages G9-G11.) (A) Let p 2 = 1 − p 1 and q 2 = 1 − q 1 and simplify (4) to show that E P , Q = D p 1 − d − c q 1 + b − d p 1 + d where D = a + d − b + c . (B) Show that if p 1 is chosen so that D p 1 − d − c = 0 , then v = a d − b c D , regardless of the value of p 1 .
Solution Summary: The author explains the theorem for 2times 2 non-strictly determined matrix game.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
Direction: Strictly write in 4 bond paper, because my activity
sheet is have 4 spaces. This is actually for maritime.
industry course, but I think geometry can do this.
use nautical almanac.
Sample Calculation (Amplitude- Sun):
On 07th May 2006 at Sunset, a vesel in position 10°00'N
0 10°00' W observed the sun bearing 288° by compass. Find
the
compass error.
LMT Sunset
07d
18h
13m
(+)00d
00h
40 м
LIT:
UTC Sunset:
07d
18h
53 m
added - since
longitude is
westerly
Declination Co7d 18h): N016° 55.5'
d(0.7):
(+)
00-6
N016 56.1'
Declination Sun:
Sin Amplitude Sin Declination (Los Latitude
- Sin 016° 56.1'/Cos 10°00'
= 0.295780189
Amplitude = WI. 2N (The prefix of amplitude is
named easterly if body is rising.
and westerly of body is setting.
The suffix is named came as
declination.)
True Bearing: 287.20
Compass Bearing
288.0°
Compass Error: 0.8' West
Chapter 10 Solutions
Finite Mathematics for Business, Economics, Life Sciences, and Social Sciences (13th Edition)
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