(a) Interpretation: The unknown element of the following equation should be determined: B 5 11 → ? + γ Concept Introduction: The reactions involving formation of new nucleus with emission of some radiation along with it from an original nucleus are known as nuclear reactions. To write a nuclear reaction, the chemical equation for the reaction must be balanced that is the sum of atomic number and mass number on both the side should be equal.

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Answer 1

Question

Chapter 10.2, Problem 10.12P

Interpretation Introduction

(a)

Interpretation:

The unknown element of the following equation should be determined: B511→ ? + γ

Concept Introduction:

The reactions involving formation of new nucleus with emission of some radiation along with it from an original nucleus are known as nuclear reactions.

To write a nuclear reaction, the chemical equation for the reaction must be balanced that is the sum of atomic number and mass number on both the side should be equal.

Interpretation Introduction

(b)

Interpretation:

The unknown element of the following equation should be determined: K1940→ ? + e−10 + γ

Concept Introduction:

The e10 particle is positively charged which is type of beta particle. The excess protons present in nucleus gets transformed to neutrons releasing positrons giving stability to nucleus.

The gamma rays are emitted when the excited molecule jumps to lower state. But the gamma emission process does not cause any change in the atomic number or mass number of the newly formed molecule.

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19.78 Write the products of the following sequences of reactions. Refer to your reaction road- maps to see how the combined reactions allow you to "navigate" between the different functional groups. Note that you will need your old Chapters 6-11 and Chapters 15-18 roadmaps along with your new Chapter 19 roadmap for these. (a) 1. BHS 2. H₂O₂ 3. H₂CrO4 4. SOCI₂ (b) 1. Cl₂/hv 2. KOLBU 3. H₂O, catalytic H₂SO4 4. H₂CrO4 Reaction Roadmap An alkene 5. EtOH 6.0.5 Equiv. NaOEt/EtOH 7. Mild H₂O An alkane 1.0 2. (CH3)₂S 3. H₂CrO (d) (c) 4. Excess EtOH, catalytic H₂SO OH 4. Mild H₂O* 5.0.5 Equiv. NaOEt/EtOH An alkene 6. Mild H₂O* A carboxylic acid 7. Mild H₂O* 1. SOC₁₂ 2. EtOH 3.0.5 Equiv. NaOEt/E:OH 5.1.0 Equiv. NaOEt 6. NH₂ (e) 1. 0.5 Equiv. NaOEt/EtOH 2. Mild H₂O* Br (f) i H An aldehyde 1. Catalytic NaOE/EtOH 2. H₂O*, heat 3. (CH,CH₂)₂Culi 4. Mild H₂O* 5.1.0 Equiv. LDA Br An ester 4. NaOH, H₂O 5. Mild H₂O* 6. Heat 7. MgBr 8. Mild H₂O* 7. Mild H₂O+

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Answer 2

Question

Chapter 10.2, Problem 10.12P

Interpretation Introduction

(a)

Interpretation:

The unknown element of the following equation should be determined: B511→ ? + γ

Concept Introduction:

The reactions involving formation of new nucleus with emission of some radiation along with it from an original nucleus are known as nuclear reactions.

To write a nuclear reaction, the chemical equation for the reaction must be balanced that is the sum of atomic number and mass number on both the side should be equal.

Interpretation Introduction

(b)

Interpretation:

The unknown element of the following equation should be determined: K1940→ ? + e−10 + γ

Concept Introduction:

The e10 particle is positively charged which is type of beta particle. The excess protons present in nucleus gets transformed to neutrons releasing positrons giving stability to nucleus.

The gamma rays are emitted when the excited molecule jumps to lower state. But the gamma emission process does not cause any change in the atomic number or mass number of the newly formed molecule.

Expert Solution & Answer

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See solution

Answer 3

Question

Chapter 10.2, Problem 10.12P

Interpretation Introduction

(a)

Interpretation:

The unknown element of the following equation should be determined: B511→ ? + γ

Concept Introduction:

The reactions involving formation of new nucleus with emission of some radiation along with it from an original nucleus are known as nuclear reactions.

To write a nuclear reaction, the chemical equation for the reaction must be balanced that is the sum of atomic number and mass number on both the side should be equal.

Interpretation Introduction

(b)

Interpretation:

The unknown element of the following equation should be determined: K1940→ ? + e−10 + γ

Concept Introduction:

The e10 particle is positively charged which is type of beta particle. The excess protons present in nucleus gets transformed to neutrons releasing positrons giving stability to nucleus.

The gamma rays are emitted when the excited molecule jumps to lower state. But the gamma emission process does not cause any change in the atomic number or mass number of the newly formed molecule.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 10.2, Problem 10.12P

Interpretation Introduction

(a)

Interpretation:

The unknown element of the following equation should be determined: B511→ ? + γ

Concept Introduction:

The reactions involving formation of new nucleus with emission of some radiation along with it from an original nucleus are known as nuclear reactions.

To write a nuclear reaction, the chemical equation for the reaction must be balanced that is the sum of atomic number and mass number on both the side should be equal.

Interpretation Introduction

(b)

Interpretation:

The unknown element of the following equation should be determined: K1940→ ? + e−10 + γ

Concept Introduction:

The e10 particle is positively charged which is type of beta particle. The excess protons present in nucleus gets transformed to neutrons releasing positrons giving stability to nucleus.

The gamma rays are emitted when the excited molecule jumps to lower state. But the gamma emission process does not cause any change in the atomic number or mass number of the newly formed molecule.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 10.2, Problem 10.12P

Interpretation Introduction

(a)

Interpretation:

The unknown element of the following equation should be determined: B511→ ? + γ

Concept Introduction:

The reactions involving formation of new nucleus with emission of some radiation along with it from an original nucleus are known as nuclear reactions.

To write a nuclear reaction, the chemical equation for the reaction must be balanced that is the sum of atomic number and mass number on both the side should be equal.

Interpretation Introduction

(b)

Interpretation:

The unknown element of the following equation should be determined: K1940→ ? + e−10 + γ

Concept Introduction:

The e10 particle is positively charged which is type of beta particle. The excess protons present in nucleus gets transformed to neutrons releasing positrons giving stability to nucleus.

The gamma rays are emitted when the excited molecule jumps to lower state. But the gamma emission process does not cause any change in the atomic number or mass number of the newly formed molecule.

Answer 6

Chapter 10.2, Problem 10.12P

Interpretation Introduction

(a)

Interpretation:

The unknown element of the following equation should be determined: B511→ ? + γ

Concept Introduction:

The reactions involving formation of new nucleus with emission of some radiation along with it from an original nucleus are known as nuclear reactions.

To write a nuclear reaction, the chemical equation for the reaction must be balanced that is the sum of atomic number and mass number on both the side should be equal.

Answer 7

Chapter 10.2, Problem 10.12P

Interpretation Introduction

(a)

Interpretation:

The unknown element of the following equation should be determined: B511→ ? + γ

Concept Introduction:

The reactions involving formation of new nucleus with emission of some radiation along with it from an original nucleus are known as nuclear reactions.

To write a nuclear reaction, the chemical equation for the reaction must be balanced that is the sum of atomic number and mass number on both the side should be equal.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The unknown element of the following equation should be determined: K1940→ ? + e−10 + γ

Concept Introduction:

The e10 particle is positively charged which is type of beta particle. The excess protons present in nucleus gets transformed to neutrons releasing positrons giving stability to nucleus.

The gamma rays are emitted when the excited molecule jumps to lower state. But the gamma emission process does not cause any change in the atomic number or mass number of the newly formed molecule.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The unknown element of the following equation should be determined: K1940→ ? + e−10 + γ

Concept Introduction:

The e10 particle is positively charged which is type of beta particle. The excess protons present in nucleus gets transformed to neutrons releasing positrons giving stability to nucleus.

The gamma rays are emitted when the excited molecule jumps to lower state. But the gamma emission process does not cause any change in the atomic number or mass number of the newly formed molecule.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 10.1 - Complete the following table for two isotopes of...Ch. 10.1 - Prob. 10.2P Ch. 10.1 - Prob. 10.3P Ch. 10.1 - Identify Q in each of the following symbols. a....Ch. 10.2 - Prob. 10.5P Ch. 10.2 - Prob. 10.6P Ch. 10.2 - Prob. 10.7P Ch. 10.2 - Prob. 10.8P Ch. 10.2 - Prob. 10.9P Ch. 10.2 - Prob. 10.10P

Solution Summary: The author explains that the chemical equation for a nuclear reaction must be balanced. The unknown element in the equation is boron, which releases gamma rays.

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