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Concept explainers
(a)
Interpretation:
The respective reactant (methyl substituted piperidine) and respective product (diene) should be given.
Concept introduction:
Generally
These quaternary ammonium salt under goes an elimination reaction easily.
Hofmann elimination:
Quaternary ammonium ion undergoes elimination when using strong base like hydroxide ion this reaction is called as Hofmann elimination.
In the Hofmann elimination, abstraction of proton form β- carbon atom which is having more number of hydrogen to result the elimination product.
(b)
Interpretation:
The respective reactant (methyl substituted piperidine) and respective product (diene) should be given.
Concept introduction:
Hofmann elimination:
Quaternary ammonium ion undergoes elimination when using strong base like hydroxide ion this reaction is called as Hofmann elimination.
In the Hofmann elimination, abstraction of proton form β- carbon atom which is having more number of hydrogen to result the elimination product.
(c)
Interpretation:
The respective reactant (methyl substituted piperidine) and respective product (diene) should be given.
Concept introduction:
Hofmann elimination:
Quaternary ammonium ion undergoes elimination when using strong base like hydroxide ion this reaction is called as Hofmann elimination. Proton abstraction is takes place in β- carbon atom which is having more number of hydrogen.
(d)
Interpretation:
The respective reactant (methyl substituted piperidine) and respective product (diene) should be given.
Concept introduction:
Generally amines can’t undergo elimination reaction, therefore amines can be converted in to quaternary ammonium halide by treating with ethyl iodide in basic solution of potassium carbonate, and this ammonium halide is treating with silver oxide to give ammonium hydroxide salt.
These quaternary ammonium salt under goes an elimination reaction easily.
Hofmann elimination:
Quaternary ammonium ion undergoes elimination when using strong base like hydroxide ion this reaction is called as Hofmann elimination.
In the Hofmann elimination, abstraction of proton form β- carbon atom which is having more number of hydrogen to result the elimination product.
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Chapter 10 Solutions
EBK ORGANIC CHEMISTRY
- 6. How many peaks would be observed for each of the circled protons in the compounds below? 8 pts CH3 CH3 ΤΙ A. H3C-C-C-CH3 I (₁₁ +1)= 7 H CI B. H3C-C-CI H (3+1)=4 H LIH)=2 C. (CH3CH2-C-OH H D. CH3arrow_forwardNonearrow_forwardQ1: Draw the most stable and the least stable Newman projections about the C2-C3 bond for each of the following isomers (A-C). Are the barriers to rotation identical for enantiomers A and B? How about the diastereomers (A versus C or B versus C)? H Br H Br (S) CH3 (R) CH3 H3C (S) H3C H Br Br H A C enantiomers H Br H Br (R) CH3 H3C (R) (S) CH3 H3C H Br Br H B D identicalarrow_forward
- 2. Histamine (below structure) is a signal molecule involved in immune response and is a neurotransmitter. Histamine features imidazole ring which is an aromatic heterocycle. Please answer the following questions regarding Histamine. b a HN =N C NH2 a. Determine hybridization of each N atom (s, p, sp, sp², sp³, etc.) in histamine N-a hybridization: N-b hybridization: N-c hybridization: b. Determine what atomic orbitals (s, p, sp, sp², sp³, etc.) of the lone pair of each N atom resided in N-a hybridization: N-b hybridization: N-c hybridization:arrow_forwardNonearrow_forward29. Use frontier orbital analysis (HOMO-LUMO interactions) to decide whether the following dimerization is 1) thermally allowed or forbidden and 2) photochemically allowed or forbidden. +arrow_forward
- 30.0 mL of 0.10 mol/L iron sulfate and 20.0 mL of 0.05 mol/L of silver nitrate solutions are mixed together. Justify if any precipitate would formarrow_forwardDoes the carbonyl group first react with the ethylene glycol, in an intermolecular reaction, or with the end alcohol, in an intramolecular reaction, to form a hemiacetal? Why does it react with the alcohol it does first rather than the other one? Please do not use an AI answer.arrow_forwardThe number of noncyclic isomers that have the composition C4H8Owith the O as part of an OH group, counting a pair of stereoisomers as1, is A. 8; B. 6; C. 9; D. 5; E. None of the other answers is correct.arrow_forward
- Nonearrow_forwardThe number of carbon skeletons that have 8 carbons, one of which istertiary is A. 7; B. More than 7; C. 6; D. 5; E. 4arrow_forwardThe azide ion is N3^-. In addition to the ionic charge, it’s three mostimportant contributing structures also have formal charges. The totalnumber of π bonds in these three contributing structures isA. 6; B. 12; C. 3; D. 9; E. None of the other answers is correct.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningOrganic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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