Chapter 10, Problem 6P

Summary Introduction

To analyze:

Analyzing the single amino acid substitution in the given $\text{β-}$ globin mutant with the help of wild type $\text{β-}$ globin form, determine the wild type template DNA sequences and the template sequence for each mutant.

$\text{β-}$ globin form	Position	Amino acid
${\text{β}}^{\text{A}}$ (wild- type)	$\text{7}$	Glu
Siriraj	$\text{7}$	Lys
San Jose	$\text{7}$	Gly
${\text{β}}^{\text{A}}$ (wild- type)	$\text{58}$	Pro
Ziguinchor	$\text{58}$	Arg
${\text{β}}^{\text{A}}$ (wild- type)	$\text{145}$	Try
Bethesda	$\text{145}$	His
Fort Gordon	$\text{145}$	Asp

Codon table

Introduction:

The word base substitution refers to the exchange of one base pair with another. Base substitution mutation in the triplet codon can result in the synthesis of the wrong amino acid thereby changing the protein structure or function.

Many hereditary anemic conditions arise due to base substitution mutation in the wild type template strand of $\text{β-}$ globin which leads to the incorporation of a wrong base pair in the codonthus causing a change in the $\text{β-}$ globin function ( Mutant $\text{β-}$ globin form).