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(a)
Interpretation:
The appropriate reagents should be given for each steps in the given reaction.
Concept introduction:
Dehydration reaction:
Removal of water molecule from the reaction of alcohol with strong acid like sulfuric acid is known as dehydration reaction.
The stability of carbocation is given below, Tertiary carbocation is more stable than the secondary and primary.
The alcohols is reaction with acids like hydrochloric acid or hydrobromic, which yield the corresponding carbocation intermediate, this carbocation intermediate undergoes elimination reaction which yields the corresponding
Hydroboration:
Hydroboration is the addition of a hydrogen-boron bond to the Carbon-Carbon, Carbon-Nitrogen, and Carbon-Oxygen double bonds and Carbon-Carbon triple bonds.
When alkene undergoes hydroboration using alkyl borane and hydrogen peroxide followed by hydrolysis which yields the alcohol. The formation of alcohol is depends on the less hindered carbon of the double bond.
In the nucleophilic substitution reaction, the
In
Reactant and nucleophile are present at the rate determination step.
The order of species involving in
Tertiary < Secondary < Primary
Ozonolysis:
Alkene reacts with ozone to gives
Oxidation of alcohol:
Alcohols reacts with hypochlorous (oxidizing agent) in the presence of acetic acid which yields the corresponding aldehyde and
Primary alcohols gives aldehyde, secondary alcohols gives ketone.
(b)
Interpretation:
The appropriate reagents should be given for each steps in the given reaction.
Concept introduction:
Dehydration reaction:
Removal of water molecule from the reaction of alcohol with strong acid like sulfuric acid is known as dehydration reaction.
The stability of carbocation is given below, Tertiary carbocation is more stable than the secondary and primary.
The alcohols is reaction with acids like hydrochloric acid or hydrobromic which yield the corresponding carbocation intermediate, this carbocation intermediate undergoes elimination reaction which yields the corresponding alkene as a product.
Hydroboration:
Hydroboration is the addition of a hydrogen-boron bond to the Carbon-Carbon, Carbon-Nitrogen, and Carbon-Oxygen double bonds and Carbon-Carbon triple bonds.
When alkene undergoes hydroboration using alkyl borane and hydrogen peroxide followed by hydrolysis which yields the alcohol. The formation of alcohol is depends on the less hindered carbon of the double bond.
In the nucleophilic substitution reaction, the rate of reaction depends on reactant as well as nucleophile, which are involved in reaction is called bimolecular nucleophilic substitution reaction.
In
Reactant and nucleophile are present at the rate determination step.
The order of species involving in
Tertiary < Secondary < Primary
Ozonolysis:
Alkene reacts with ozone which cleaves the double bond followed by work up with dimethyl sulfide to forms ketone with aldehyde is known as ozonolysis.
Oxidation of alcohol:
Alcohols reaction with hypochlorous (oxidizing agent) in the presence of acetic acid which yields the corresponding aldehyde and ketones.
Primary alcohols gives aldehyde, secondary alcohols gives ketone.
(c)
Interpretation:
The appropriate reagents should be given for each steps in the given reaction.
Concept introduction:
Dehydration reaction:
Removal of water molecule from the reaction of alcohol with strong acid like sulfuric acid is known as dehydration reaction.
The stability of carbocation is given below, Tertiary carbocation is more stable than the secondary and primary.
The alcohols is reaction with acids like hydrochloric acid or hydrobromic which yield the corresponding carbocation intermediate, this carbocation intermediate undergoes elimination reaction which yields the corresponding alkene as a product.
Hydroboration:
Hydroboration is the addition of a hydrogen-boron bond to the Carbon-Carbon, Carbon-Nitrogen, and Carbon-Oxygen double bonds and Carbon-Carbon triple bonds.
When alkene undergoes hydroboration using alkyl borane and hydrogen peroxide followed by hydrolysis which yields the alcohol. The formation of alcohol is depends on the less hindered carbon of the double bond.
In the nucleophilic substitution reaction, the rate of reaction depends on reactant as well as nucleophile, which are involved in reaction is called bimolecular nucleophilic substitution reaction.
In
Reactant and nucleophile are present at the rate determination step.
The order of species involving in
Tertiary < Secondary < Primary
Ozonolysis:
Alkene reacts with ozone which cleaves the double bond followed by work up with dimethyl sulfide to forms ketone with aldehyde is known as ozonolysis.
Oxidation of alcohol:
Alcohols reaction with hypochlorous (oxidizing agent) in the presence of acetic acid which yields the corresponding aldehyde and ketones.
Primary alcohols gives aldehyde, secondary alcohols gives ketone.
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Chapter 10 Solutions
Organic Chemistry Study Guide and Solutions Manual, Books a la Carte Edition (8th Edition)
- 2. Read paragraph 3.4 in your textbook ("Chiral Molecules"), and explain if Cobalt(ethylenediamine) 33+ shown in previous problem is a chiral species. If yes, draw projections of both enantiomers as mirror images, analogous to mirror projections of hands (below). Mirror (4 points)arrow_forward3. Borane (BH3) belongs to D3h point group. Consider the vibrational (stretching) modes possible for B-H bonds under D3h symmetry. Using the methods we used in class, construct the reducible representation I, and break it down into irreducible representations using the character table provided. Sketch those modes, indicate whether they are IR-active. (6 points) D3h E 2C3 3C2 σh 283 30% A₁' 1 1 1 1 1 1 x² + y², z² 1 -1 1 1 -1 R₂ E' 2 0 2 0 (x, y) (x² - y², xy) " A₁" 1 1 -1 A2" 1 -1 -1 1 Z E" 2 -1 0 -2 1 0 (Ry, Ry) (xz, yz)arrow_forward1. List all the symmetry elements, and assign the compounds to proper point groups: a) HCIBrC-BrCIH Cl Br H (2 points) H Br b) Pentacarbonylmanganese(I)bromide Br OEC-Mn-CEO 00- c) Phenazine (aromatic molecule, with delocalized bonding) 1 d) Cobalt(ethylenediamine)33+ (just the cation) 3+ H₂N H₂ .NH2 (CI)3 NH2 H2 H₂N. (2 points) (2 points) (2 points)arrow_forward
- Hello, I desperately need help figuring out 8-14; I also wanted to see if you would mind letting me know if I picked the right degree as my melting points on the two graphs. Please and thank you in advance! All the information is provided.arrow_forwardThe reaction: A + B ⇌ 2 C, can be represented by the equilibrium expression, KC =[C]2[A][B]=258 at 520K.When 1.00 M of C was allowed to reach equilibrium and 0.055 M of A was formed. If this reaction wasperformed at the same temperature using 0.500 M C, what would the equilibrium concentration of Abe?arrow_forward1. What is the functional group of an alcohol and a phenol? 2. Why are some alcohols soluble in water? 3. Classify each of the following alcohols as primary, secondary or tertiary. a. 3-pentanol b. 2-methyl-2-butanol c. 1-propanolarrow_forward
- I need help with B2 using the information in B1. This is for my lab notebook, and I got confused on number 2. Please help.arrow_forward4. Aluminum has a face-centered cubic structure. The unit cell length is 4.05Å. Calculate the radius of Al atom in the metal. (5 points).arrow_forwardHF and HNO2 are both considered weak acids. Given the following K values for their dissociationequations, which is the weaker of these two weak acids?HF (aq) ⇌ H+(aq) + F –(aq) K=6.6 x10-4 HNO2 (aq) ⇌ H+(aq) + NO2–(aq) K=7.2 X 10-4arrow_forward
- The equilibrium constant for this reaction is 5.88 x 104. If concentration of the lead ion is 5.24 M, whatis the concentration of the chloride ion?Pb2+(aq) + 2 Cl- (aq) ⇌ PbCl2(s)arrow_forwardc. 1-propanoi 4. If you add chromate, an oxidizing agent, to each of the following, would a green Cr3+ solution be formed? a. 3-pentanol b. 2-methyl-2-butanol c. 1-propanol 5. If an alcohol solution has a pH of 5, would it be a primary alcohol, a secondary alcohol, a tertiary alcohol, or a phenol?arrow_forwardGiven the reaction: A(aq) + B(aq) ⇌ 2C(aq) + D(aq). 2.00 moles of each reactant were dissolved into 1.00 literof water. The reaction reached equilibrium, and at equilibrium the concentration of A was 1.60 M.A) Calculate the equilibrium concentrations for each substance. B) Write the equilibrium constant expression. C) Calculate the value for the equilibrium constant, Keq.arrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
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