1 SEM ACC W/RAVEN CARDED
12th Edition
ISBN: 9781265486297
Author: Raven
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Textbook Question
Chapter 10, Problem 5A
The main difference between bacterial cell division and eukaryotic cell division is that
a. because bacteria only have one chromosome, they can count the number of copies in the cell.
b. eukaryotes mark their chromosomes to identify them and bacteria do not.
c. bacterial
d. None of the above is correct.
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1) Look at the ideal results. Were your predictions accurate, and how did they compare with your results?
2) You used aseptic technique during this lab. Why is it important to work in a sterile manner when working with bacteria in the lab?
3) Why are the cells incubated at 42°C?
Overview of Transformation Protocol
-Prepare competent bacteria for transformation:
Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure.
Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed.
-Transformation procedure:
Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA.
Add CaCl2 to both tubes.
Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube.
Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes.
Add recovery broth to both tubes.
Incubate both tubes in a 37 C water bath for 5 minutes.
Questions:
1) What differences would you expect to see between the…
Overview of Transformation Protocol
-Prepare competent bacteria for transformation:
Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure.
Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed.
-Transformation procedure:
Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA.
Add CaCl2 to both tubes.
Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube.
Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes.
Add recovery broth to both tubes.
Incubate both tubes in a 37 C water bath for 5 minutes.
Questions:
1)What is the selectable marker in this experiment? How…
Chapter 10 Solutions
1 SEM ACC W/RAVEN CARDED
Ch. 10.1 - Prob. 1LOCh. 10.2 - Prob. 1LOCh. 10.2 - Distinguish between homologues and sister...Ch. 10.2 - Prob. 3LOCh. 10.3 - Describe the eukaryotic cell cycle.Ch. 10.4 - Prob. 1LOCh. 10.4 - Prob. 2LOCh. 10.5 - Describe the phases of mitosis.Ch. 10.5 - Explain the importance of metaphase.Ch. 10.5 - Compare cytokinesis in plants and animals.
Ch. 10.6 - Prob. 1LOCh. 10.6 - Prob. 2LOCh. 10.7 - Prob. 1LOCh. 10.7 - Prob. 2LOCh. 10 - Binary fission in prokaryotes does not require the...Ch. 10 - Chromatin is composed of a. RNA and protein. b....Ch. 10 - What is a nucleosome? a. A region in the cells...Ch. 10 - What is the role of cohesin proteins in cell...Ch. 10 - The kinetochore is a structure that functions to...Ch. 10 - Separation of the sister chromatids occurs during...Ch. 10 - Why is cytokinesis an important part of cell...Ch. 10 - What steps in the cell cycle represent...Ch. 10 - Cyclin-dependent kinases (Cdks) are regulated by...Ch. 10 - Prob. 2ACh. 10 - Genetically, proto-oncogenes act in a dominant...Ch. 10 - The metaphase to anaphase transition involves a....Ch. 10 - The main difference between bacterial cell...Ch. 10 - In animal cells, cytokinesis is accomplished by a...Ch. 10 - Regulation of the cell cycle is very complex and...Ch. 10 - Review you knowledge of signaling pathways...Ch. 10 - Compare and contrast how mutations in cellular...
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