Explanation Given: The number of young adults selected n = 1000 The probability of success on a single trial p = 0.15 Formula used: The expression for the mean and the standard deviation for binomial distribution is: μ = n p σ = n p ( 1 − p ) The z -score for any value x : z = x − μ σ Here, μ is the mean, σ is the standard deviation, n is the number of trials and p is the probability of success on a single trial. Calculation: Use the formula of mean, standard deviation and z -score. Substitute 1000 for n and 0.15 for p as: μ = n p = 1000 ( 0.15 ) = 150 σ = n p ( 1 − p ) = 1000 ( 0

MATH W/APPLICAT.W/NOTES GDE +ACCESS CODE

11th Edition

ISBN: 9781323751671

Author: Lial

Publisher: PEARSON C

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Chapter 10, Problem 54RE

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To calculate: The probability that 165 or fewer young adults live in their parents’ home, while a random sample of 1000 adults are considered.

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Chapter 10, Problem 53RE

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Chapter 10 Solutions

MATH W/APPLICAT.W/NOTES GDE +ACCESS CODE

Ch. 10.1 - Checkpoint 1 A restaurant trade group commissioned...Ch. 10.1 - Checkpoint 2 Make a histogram and a frequency...Ch. 10.1 - Checkpoint 3 Make a stem-and-leaf plot for the...Ch. 10.1 - Checkpoint 4 List the original data for the...Ch. 10.1 - Checkpoint 5 Characterize the shape of the...Ch. 10.1 - SP 500 Stocks The data for Exercises 1 -4 consist...Ch. 10.1 - SP 500 Stocks The data for Exercises 1 -4 consist...Ch. 10.1 - SP 500 Stocks The data for Exercises 1 -4 consist...Ch. 10.1 - SP 500 Stocks The data for Exercises 1 -4 consist...Ch. 10.1 - The data for Exercises 5-10 consist of random...

Ch. 10.1 - The data for Exercises 5-10 consist of random...Ch. 10.1 - The data for Exercises 5-10 consist of random...Ch. 10.1 - The data for Exercises 5-10 consist of random...Ch. 10.1 - The data for Exercises 5-10 consist of random...Ch. 10.1 - The data for Exercises 5-10 consist of random...Ch. 10.1 - For Exercises 11-20, construct a stem-and-leaf...Ch. 10.1 - For Exercises 11-20, construct a stem-and-leaf...Ch. 10.1 - For Exercises 11-20, construct a stem-and-leaf...Ch. 10.1 - Prob. 14E Ch. 10.1 - For Exercises 11-20, construct a stem-and-leaf...Ch. 10.1 - For Exercises 11-20, construct a stem-and-leaf...Ch. 10.1 - Prob. 17E Ch. 10.1 - Prob. 18E Ch. 10.1 - For Exercises 11-20, construct a stem-and-leaf...Ch. 10.1 - For Exercises 11-20, construct a stem-and-leaf...Ch. 10.1 - Describe the shape of each of the given...Ch. 10.1 - Describe the shape of each of the given...Ch. 10.1 - Describe the shape of each of the given...Ch. 10.1 - Describe the shape of each of the given...Ch. 10.1 - Student Loan Defaults The following histogram...Ch. 10.1 - Stocks The following histogram shows the stock...Ch. 10.1 - Cat Ownership The stem-and-leaf plot below...Ch. 10.1 - Personal Bankruptcies The stem-and-leaf plot below...Ch. 10.1 - 29. 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When is the median the most appropriate...Ch. 10.2 - 21. When would the mode be an appropriate measure...Ch. 10.2 - Pet Ownership For Exercises 22 and 23, the...Ch. 10.2 - Pet Ownership For Exercises 22 and 23, the...Ch. 10.2 - 24. To predict the outcome of the next...Ch. 10.2 - Work each problem. (See Example 6.) MLB Payrolls...Ch. 10.2 - Work each problem. (See Example 6.) NFL Team...Ch. 10.2 - Work each problem. (See Example 6.) 27. Business...Ch. 10.2 - Work each problem. (See Example 6.) Sirius XM...Ch. 10.2 - Work each problem. (See Example 6.) 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The peak in a normal curve occurs directly...Ch. 10.4 - Prob. 2E Ch. 10.4 - Prob. 3E Ch. 10.4 - Prob. 4E Ch. 10.4 - Prob. 5E Ch. 10.4 - Prob. 6E Ch. 10.4 - Prob. 7E Ch. 10.4 - Prob. 8E Ch. 10.4 - Find the percentage of the total area under the...Ch. 10.4 - Prob. 10E Ch. 10.4 - Prob. 11E Ch. 10.4 - Prob. 12E Ch. 10.4 - Prob. 13E Ch. 10.4 - Prob. 14E Ch. 10.4 - Prob. 15E Ch. 10.4 - Prob. 16E Ch. 10.4 - Prob. 17E Ch. 10.4 - Prob. 18E Ch. 10.4 - Prob. 19E Ch. 10.4 - 20. 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The probability that 165 or fewer young adults live in their parents’ home, while a random sample of 1000 adults are considered.

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Chapter 10 Solutions