DATABASE SYSTEMS-MINDTAPV2.0
13th Edition
ISBN: 9780357427873
Author: Coronel
Publisher: CENGAGE L
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Chapter 10, Problem 4RQ
Explanation of Solution
List of transaction properties:
The transaction process has the list of properties in each individual transaction. The transaction must display these properties for consistent state. They are:
- Atomicity
- Consistency
- Isolation
- Durability
These above four transactions are referred as ACID test. The other additional transaction property is “Serializability”.
Explanation of transaction properties:
Atomicity:
- This property requires all part of the transaction (SQL commands) must be completed. Otherwise, the transaction is aborted. \
- For example: if the transaction T2 has three SQL commands, all three commands must successfully complete in the transaction. If not it is considered as inconsistent state. Hence, the atomicity property ensures the consistent state of the transaction.
Consistency:
- The property indicates the permanence of
database consistency. If the transaction is completed, the database will move one consistent state to another consistent state.
Isolation:
- This property is used for database transaction and the data item is accessed but one transaction cannot be accessed by any other transactions until the first one ends...
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Consider the following scenario in which host 10.0.0.1 is communicating with an external SMTP mail server at IP
address 128.119.40.186.
NAT translation table
WAN side addr
LAN side addr
(c), 5051
(d), 3031
S: (e),5051
SMTP
B
D (f.(g)
10.0.0.4
server
138.76.29.7
128.119.40.186
(a) is the source IP address at A, and its value.
S: (a),3031
D: (b), 25
10.0.0.1
A
10.0.0.2.
1. 138.76.29.7
10.0.0.3
6.3A-3. Multiple Access protocols (3). Consider the figure below, which shows the arrival of 6
messages for transmission at different multiple access wireless nodes at times t=0.1, 1.4, 1.8, 3.2,
3.3, 4.1. Each transmission requires exactly one time unit.
1
t=0.0
2
3
45
t=1.0
t-2.0
t-3.0
6
t=4.0
t-5.0
For the CSMA protocol (without collision detection), indicate which packets are successfully
transmitted. You should assume that it takes .2 time units for a signal to propagate from one node to
each of the other nodes. You can assume that if a packet experiences a collision or senses the
channel busy, then that node will not attempt a retransmission of that packet until sometime after
t=5. Hint: consider propagation times carefully here. (Note: You can find more examples of problems similar to this here B.]
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Just wanted to know, if you had a scene graph, how do you get multiple components from a specific scene node within a scene graph? Like if I wanted to get a component from wheel from the scene graph, does that require traversing still?
Like if a physics component requires a transform component and these two component are part of the same scene node. How does the physics component knows how to get the scene object's transform it is attached to, this being in a scene graph?
Chapter 10 Solutions
DATABASE SYSTEMS-MINDTAPV2.0
Ch. 10 - Prob. 1RQCh. 10 - Prob. 2RQCh. 10 - Prob. 3RQCh. 10 - Prob. 4RQCh. 10 - Prob. 5RQCh. 10 - Prob. 6RQCh. 10 - Prob. 7RQCh. 10 - Prob. 8RQCh. 10 - Prob. 9RQCh. 10 - Prob. 10RQ
Ch. 10 - Prob. 11RQCh. 10 - Prob. 12RQCh. 10 - Prob. 13RQCh. 10 - Prob. 14RQCh. 10 - Prob. 15RQCh. 10 - Prob. 16RQCh. 10 - Prob. 17RQCh. 10 - Prob. 1PCh. 10 - Prob. 2PCh. 10 - Prob. 3PCh. 10 - Prob. 4PCh. 10 - Prob. 5PCh. 10 - Prob. 6PCh. 10 - Prob. 7PCh. 10 - Prob. 8PCh. 10 - Prob. 9PCh. 10 - Prob. 10PCh. 10 - Prob. 11P
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