Chemistry for Changing Times
14th Edition
ISBN: 9780134212777
Author: John W. Hill; Terry W. McCreary
Publisher: Pearson Education (US)
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Question
Chapter 10, Problem 38AP
Interpretation Introduction
Interpretation:The monomer from which
Concept Introduction:
- Addition polymerization, in which the monomer undergoing polymerization do notlose any atoms in the formation of a
polymer . - Condensation polymerization, in which the monomer undergoing polymerization loose few atoms, such as water in the formation of a polymer.
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For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
R lactam or lactone considering as weak acid or weak base and why
Chapter 10 Solutions
Chemistry for Changing Times
Ch. 10 - Prob. 1RQCh. 10 - Prob. 2RQCh. 10 - Prob. 3RQCh. 10 - Prob. 4RQCh. 10 - Prob. 5RQCh. 10 - Prob. 6RQCh. 10 - Prob. 7RQCh. 10 - Prob. 8RQCh. 10 - Prob. 9RQCh. 10 - Prob. 10RQ
Ch. 10 - Prob. 11RQCh. 10 - Prob. 12RQCh. 10 - Prob. 13PCh. 10 - Prob. 14PCh. 10 - Prob. 15PCh. 10 - Prob. 16PCh. 10 - Prob. 17PCh. 10 - Prob. 18PCh. 10 - Prob. 19PCh. 10 - Prob. 20PCh. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - Prob. 25PCh. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Prob. 29PCh. 10 - Prob. 30PCh. 10 - Prob. 31PCh. 10 - Prob. 32PCh. 10 - Prob. 33PCh. 10 - Prob. 34PCh. 10 - Prob. 35APCh. 10 - Prob. 36APCh. 10 - Prob. 37APCh. 10 - Prob. 38APCh. 10 - Prob. 39APCh. 10 - Prob. 40APCh. 10 - Prob. 41APCh. 10 - Prob. 42APCh. 10 - Prob. 43APCh. 10 - Prob. 44APCh. 10 - Prob. 45APCh. 10 - Prob. 46APCh. 10 - Prob. 47APCh. 10 - Prob. 48APCh. 10 - Prob. 49APCh. 10 - Prob. 50APCh. 10 - Prob. 51APCh. 10 - Prob. 52APCh. 10 - Prob. 53APCh. 10 - Prob. 54APCh. 10 - Prob. 55APCh. 10 - Prob. 56APCh. 10 - Prob. 57APCh. 10 - Prob. 10.1CTECh. 10 - Prob. 10.2CTECh. 10 - Prob. 10.3CTECh. 10 - Prob. 10.4CTECh. 10 - Prob. 1CGPCh. 10 - Prob. 2CGPCh. 10 - Prob. 3CGPCh. 10 - Prob. 4CGPCh. 10 - Prob. 5CGPCh. 10 - Prob. 6CGPCh. 10 - Prob. 7CGPCh. 10 - Prob. 8CGPCh. 10 - Prob. 1CHQCh. 10 - Prob. 2CHQCh. 10 - Prob. 3CHQCh. 10 - Prob. 4CHQ
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Similar questions
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