Chemistry for Changing Times
14th Edition
ISBN: 9780134212777
Author: John W. Hill; Terry W. McCreary
Publisher: Pearson Education (US)
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Chapter 10, Problem 14P
Interpretation Introduction
Interpretation: Structure of linear low-density polyethylene (LLDPE) should be drawn and explain how the properties of LLDPE are related to its structure.
Concept Introduction: Linear Low Density Polyethylene is formed by copolymerization of ethylene, which is a monomer with longer chain olefins.
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Michael Reactions
19.52 Draw the products from the following Michael addition reactions.
1.
H&C CH
(a)
i
2. H₂O*
(b)
OEt
(c)
EtO
H₂NEt
(d)
ΕΙΟ
+
1. NaOEt
2. H₂O'
H
H
1. NaOEt
2. H₂O*
Rank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic.
НОН НЬ
OHd
Онс
Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left?
?
starting
material
target
If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area.
Be sure you follow the standard ALEKS rules for submitting syntheses.
+ More...
Note for advanced students: you may assume that you are using a large excess of benzene as your starting material.
C
:0
T
Add/Remove step
G
Chapter 10 Solutions
Chemistry for Changing Times
Ch. 10 - Prob. 1RQCh. 10 - Prob. 2RQCh. 10 - Prob. 3RQCh. 10 - Prob. 4RQCh. 10 - Prob. 5RQCh. 10 - Prob. 6RQCh. 10 - Prob. 7RQCh. 10 - Prob. 8RQCh. 10 - Prob. 9RQCh. 10 - Prob. 10RQ
Ch. 10 - Prob. 11RQCh. 10 - Prob. 12RQCh. 10 - Prob. 13PCh. 10 - Prob. 14PCh. 10 - Prob. 15PCh. 10 - Prob. 16PCh. 10 - Prob. 17PCh. 10 - Prob. 18PCh. 10 - Prob. 19PCh. 10 - Prob. 20PCh. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - Prob. 25PCh. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Prob. 29PCh. 10 - Prob. 30PCh. 10 - Prob. 31PCh. 10 - Prob. 32PCh. 10 - Prob. 33PCh. 10 - Prob. 34PCh. 10 - Prob. 35APCh. 10 - Prob. 36APCh. 10 - Prob. 37APCh. 10 - Prob. 38APCh. 10 - Prob. 39APCh. 10 - Prob. 40APCh. 10 - Prob. 41APCh. 10 - Prob. 42APCh. 10 - Prob. 43APCh. 10 - Prob. 44APCh. 10 - Prob. 45APCh. 10 - Prob. 46APCh. 10 - Prob. 47APCh. 10 - Prob. 48APCh. 10 - Prob. 49APCh. 10 - Prob. 50APCh. 10 - Prob. 51APCh. 10 - Prob. 52APCh. 10 - Prob. 53APCh. 10 - Prob. 54APCh. 10 - Prob. 55APCh. 10 - Prob. 56APCh. 10 - Prob. 57APCh. 10 - Prob. 10.1CTECh. 10 - Prob. 10.2CTECh. 10 - Prob. 10.3CTECh. 10 - Prob. 10.4CTECh. 10 - Prob. 1CGPCh. 10 - Prob. 2CGPCh. 10 - Prob. 3CGPCh. 10 - Prob. 4CGPCh. 10 - Prob. 5CGPCh. 10 - Prob. 6CGPCh. 10 - Prob. 7CGPCh. 10 - Prob. 8CGPCh. 10 - Prob. 1CHQCh. 10 - Prob. 2CHQCh. 10 - Prob. 3CHQCh. 10 - Prob. 4CHQ
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- The following equations represent the formation of compound MX. What is the AH for the electron affinity of X (g)? X₂ (g) → 2X (g) M (s) → M (g) M (g) M (g) + e- AH = 60 kJ/mol AH = 22 kJ/mol X (g) + e-X (g) M* (g) +X (g) → MX (s) AH = 118 kJ/mol AH = ? AH = -190 kJ/mol AH = -100 kJ/mol a) -80 kJ b) -30 kJ c) -20 kJ d) 20 kJ e) 156 kJarrow_forwardA covalent bond is the result of the a) b) c) d) e) overlap of two half-filled s orbitals overlap of a half-filled s orbital and a half-filled p orbital overlap of two half-filled p orbitals along their axes parallel overlap of two half-filled parallel p orbitals all of the abovearrow_forwardCan the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left? starting material target If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area. Be sure you follow the standard ALEKS rules for submitting syntheses. + More... Note for advanced students: you may assume that you are using a large excess of benzene as your starting material. C T Add/Remove step X ноarrow_forward
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