ORGANIC CHEM. VOL.1+2-W/WILEYPLUS
ORGANIC CHEM. VOL.1+2-W/WILEYPLUS
12th Edition
ISBN: 9781119304241
Author: Solomons
Publisher: WILEY C
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Chapter 10, Problem 36P
Interpretation Introduction

Interpretation:

The radical mechanism for the given process is to be written.

Concept introduction:

Electrophiles are electron-deficient species, which has positive or partially positive charge. Lewis acids are electrophiles, which accept electron pair.

Nucleophiles are electron-rich species, which has negative or partially negative charge. Lewis bases are nucleophiles, which donate electron pair.

Radical is an atom or molecule that has an unpaired valence electron. These unpaired electrons make radical highly chemically reactive.

Substitution reaction: A reaction in which one of the hydrogen atoms of a hydrocarbon or a functional group is substituted by any other functional group is called substitution reaction.

Elimination reaction: A reaction in which two substituent groups are detached and a double bond is formed is called elimination reaction.

Addition reaction: It is the reaction in which unsaturated bonds are converted to saturated molecules by the addition of molecules.

Reduction is a process in which hydrogen atoms are added to a compound.

Homolytic fission is that fission in which each atom in the bond has an electron which results in species called free radical.

In heterolytic fission, when covalent bond is broken, the shared pair of electron is taken by one of the atoms.

A type of halogenation in which alkanes and aromatics, which are alkyl substituted, react chemically in presence of light is known as free radical halogenation. It involves chain initiation, propagation, and termination steps in its whole mechanism. The free radical halogenation reaction is used in industries to synthesize dichloromethane and chloroform.

2,2'azobisisobutyronitrile(AIBN) undergoes homolytic cleavage to form isobutyronitrile radical, which helps in the initiation of the reaction.

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Alcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…
methanol + CH3OH Suppose you were told that the above reaction was a substitution reaction but you were not told the mechanism. Evaluate the following categories to determine the reaction mechanism and then draw the structure of the major organic product. Type of alkyl halide: Type of nucleophile: Solvent: Is the product racemic?
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