Chapter 10, Problem 35E

Interpretation Introduction

Interpretation:

The concentration of ethanol in wine has to be calculated in terms of mass percent and molality.

Concept Introduction:

Mass percentage of a compound can be defined by as calculated mass of the compound to the total mass of the compound whole multiplied by $\text{100}$ . The mass percentage of a compound can be given by the equation,

$\text{Mass}\text{percentage(\%)=}\frac{\text{Calculated}\text{mass(g)}}{\text{Total}\text{mass(g)}}\text{×100}$

Molality of a solution also called as molal concentration can be defined as the mass of solute in grams to the mass of the solvent in kilograms. It can be given by the equation,

$\text{Molality(mol}{\text{kg}}^{\text{-1}}\text{)=}\frac{\text{Mass}\text{of}\text{solue(in}\text{g)}}{\text{Mass}\text{of}\text{solvent(in}\text{kg)}}$