Chemistry with Access Code, Hybrid Edition
9th Edition
ISBN: 9781285188492
Author: Steven S. Zumdahl
Publisher: CENGAGE L
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Chapter 10, Problem 14Q
Interpretation Introduction
Interpretation:
- The atoms other than hydrogen that are necessary for the formation of hydrogen bond should be mentioned.
- The role of hydrogen on the can contribution to the strength of dipole-dipole forces should be discussed.
Concept introduction:
- Dipole-dipole interactions are the intermolecular forces exist in polar molecules. These interactions do operate and have significance only if the molecules do exist nearby with each other. It does readily become weak if the molecules move apart. So this interaction cannot always be permanent.
- Hydrogen bonding can be termed as a kind of polar covalent formed between hydrogen and high electronegative atoms like N, O, and F when both these atoms are present in the same compound.
- The dipole-dipole interactions are stronger in hydrogen bond due to the high polar nature of the bond. As a result hydrogen bonds are not as weak as usual dipole-dipole interactions. Hence they are special type of dipole-dipole forces.
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Students have asked these similar questions
5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the
product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15%
glycerin by weight.
If the original charge is 500 kg, evaluate;
e. The ratio of sucrose to water in the original charge (wt/wt).
f. Moles of CO2 evolved.
g. Maximum possible amount of ethanol that could be formed.
h. Conversion efficiency.
i. Per cent excess of excess reactant.
Reactions:
Inversion reaction: C12H22O11 + H2O →2C6H12O6
Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2
Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3
Show work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?
13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the
molecule depicted below.
Bond B
2°C. +2°C. cleavage
Bond A
•CH3 + 26.← Cleavage
2°C. +
Bond C
+3°C•
CH3 2C
Cleavage
E
2°C. 26.
weakest bond
Intact molecule
Strongest 3°C 20.
Gund
Largest
argest
a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in
appropriate boxes.
C
Weakest
bond
A
Produces
Most
Bond
Strongest
Bond
Strongest Gund
produces least stable
radicals
Weakest
Stable radical
b. (4pts) Consider the relative stability of all cleavage products that form when bonds A,
B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B,
and C are all carbon radicals.
i. Which ONE cleavage product is the most stable? A condensed or bond line
representation is fine.
13°C. formed in
bound C
cleavage
ii. Which ONE cleavage product is the least stable? A condensed or bond line
representation is fine.
• CH3
methyl radical
Formed in Gund A Cleavage
c.…
Chapter 10 Solutions
Chemistry with Access Code, Hybrid Edition
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