UNDERSTANDING THE UNIVERSE(LL)-W/CODE
3rd Edition
ISBN: 9780393869903
Author: PALEN
Publisher: NORTON
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Chapter 10, Problem 12QAP
To determine
The energy of photon that is not possible during emission.
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QUESTION TWO PLEASE..
An electron in a Hydrogen atom is in energy level n=7 and drops down into the ground state (n=1). What is the energy of the photon that is emitted in units of eV?
Chapter 10 Solutions
UNDERSTANDING THE UNIVERSE(LL)-W/CODE
Ch. 10.1 - Prob. 10.1CYUCh. 10.2 - Prob. 10.2CYUCh. 10.3 - Prob. 10.3CYUCh. 10.4 - Prob. 10.4CYUCh. 10 - Prob. 1QAPCh. 10 - Prob. 2QAPCh. 10 - Prob. 3QAPCh. 10 - Prob. 4QAPCh. 10 - Prob. 5QAPCh. 10 - Prob. 6QAP
Ch. 10 - Prob. 7QAPCh. 10 - Prob. 8QAPCh. 10 - Prob. 9QAPCh. 10 - Prob. 10QAPCh. 10 - Prob. 11QAPCh. 10 - Prob. 12QAPCh. 10 - Prob. 13QAPCh. 10 - Prob. 14QAPCh. 10 - Prob. 15QAPCh. 10 - Prob. 16QAPCh. 10 - Prob. 17QAPCh. 10 - Prob. 18QAPCh. 10 - Prob. 19QAPCh. 10 - Prob. 20QAPCh. 10 - Prob. 21QAPCh. 10 - Prob. 22QAPCh. 10 - Prob. 23QAPCh. 10 - Prob. 24QAPCh. 10 - Prob. 25QAPCh. 10 - Prob. 26QAPCh. 10 - Prob. 27QAPCh. 10 - Prob. 28QAPCh. 10 - Prob. 29QAPCh. 10 - Prob. 31QAPCh. 10 - Prob. 32QAPCh. 10 - Prob. 33QAPCh. 10 - Prob. 34QAPCh. 10 - Prob. 35QAPCh. 10 - Prob. 36QAPCh. 10 - Prob. 37QAPCh. 10 - Prob. 38QAPCh. 10 - Prob. 39QAPCh. 10 - Prob. 40QAPCh. 10 - Prob. 41QAPCh. 10 - Prob. 42QAPCh. 10 - Prob. 43QAPCh. 10 - Prob. 44QAPCh. 10 - Prob. 45QAP
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- What is the frequency of the photon absorbed when the hydrogen atom makes the transition from the ground state to the n=4 state?arrow_forwardExample: An electron in a hydrogen atom drops from energy level E4 to energy level E2. What is the frequency of the emitted photon, and which line in the emission spectrum corresponds to this event? E6 E = -0.378 eV Step 1: Es E = -0.544 eV - E= -0.850 eV Find the energy of the photon. E E = Einitial - Efinal E3 E=-1.51 eV = (-0.850 eV) - (-3.40 eV) = 2.55 eV Step 2: Use Plank's equation for frequency. E₂ E= -3.40 eV 12 E E = hf; f = h (2.55 eV) (1.60 x 10-191 6.63 x 10-34 Js f= 6.15 x 10¹4 Hz Line 3 is in the visible part of the electromagnetic spectrum and appears to be blue. The frequency f = 6.15 x 10¹4 Hz lies within the range of the visible spectrum and is toward the violet end, so it is reasonable that light of this frequency would be visible blue light. Step 3: Find the corresponding line in the emission spectrum. Examination of the diagram shows that the electron's jump from energy level E4 to energy level E2 corresponds to Line 3 in the emission spectrum. 3 Incoming photon…arrow_forwardWhat is the frequency of light (in Hz) of a photon emitted when an electron in a hydrogen atom undergoes a transition from the n = 4 energy state to the n=2 energy state? Express your answer to at least two significant figures.arrow_forward
- What is the wavelength of the light emitted when hydrogen atoms go from n = 9 to n = 3? Please give your answer in nanometers.arrow_forwardWhat are the energies and vacuum wavelengths of all the possible photons emitted when an electron moves from the n=3 to the n=1 orbit of the hydrogen atom?arrow_forwardFind the frequency of the photon emitted when hydrogen makes a transition between energy level 6 to energy level 4. h = 6.62 x 10-34m² · kg/s c = 3 x 10®m/sarrow_forward
- When an electron moves from the n=5 orbit to the n=4 orbit of a hydrogen atom, a photon of light is emitted a. What is the energy of this photon, in joules? b. What is the frequency of this radiation, in hertz? c. What is the wavelength of this radiation, in nanometers?arrow_forwarda) What is the wavelength lambda (m) of green light having a frequency of 5.7 x 10^14 Hz. b). Determine the energy (J) of each photon of the green light using the formula E = hf, where E is energy in Joules, h is Planck's constant (6.62 x 10^-34 J/s) and f is frequency in Hz.arrow_forwardThe electron in a hydrogen atom jumps from the E5 eV ev E₁ = = What is the (positive) energy and wavelength of the photon emitted? eV E photon λ = λ = = n₁ 5 state to the nf = nm Follow the same steps to find the wavelength of the photon emitted when the electron in the hydrogen atom jumps from the n = nm = 1 state. What are the energies of these two states? 13 state to the and n₁ = 4 state.arrow_forward
- Calculate the velocity (in m/s) of an electron that has a wavelength of (2.6000x10^-12) m.arrow_forwardThe two nuclei in the carbon monoxide (CO) molecules are 0.1128 nm apart. The mass of the carbon atom is 1.993x10-26 kg. The mass of the oxygen atom is 2.656x10-26 kg.What is the wavelength of the photon emitted in the transition from first excited state to the ground state? (Give your answer in mm.)arrow_forwardPhotons of a certain ultraviolet light have an energy of 6.70 ✕ 10−19 J. (a) What is the frequency of this UV light? Hz(b) Use ? = c/f to calculate its wavelength in nanometers (nm). nmarrow_forward
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