Pre-Algebra, Student Edition
Pre-Algebra, Student Edition
1st Edition
ISBN: 9780078885150
Author: McGraw-Hill
Publisher: Glencoe/McGraw-Hill
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Chapter 10, Problem 11STP

(a)

To determine

To find: the length of R¯S¯,S¯T¯, and R¯T¯ .

(a)

Expert Solution
Check Mark

Answer to Problem 11STP

Thelength of R¯S¯,S¯T¯ is 7.07 

The length of R¯T¯ is  8.50

Explanation of Solution

Given:

  Pre-Algebra, Student Edition, Chapter 10, Problem 11STP

Calculation:

The objective of the question is to determine the measure of the sides of a triangle whose coordinates are given.

Given the two points (x1,y1) and (x2,y2) , the distance d between these points is given by the formula:

  d2=(y2 y1)2+(x2x1)2

The triangle is as given in the diagram.

The objective of the question is to determine the measure of the sides of a triangle whose coordinates are given.

Observe the positions of the coordinates and find out the coordinates of each point of the triangle

For example point R is 2 unit to the right of origin and 4 units upwards. Hence its coordinates will be (2,4)

Similarly, S(3,-3) and T(-4,-2)

The coordinates are

  R(2,4), S(3,3) & T(4,2)

Apply distance formula by keeping the values of the two coordinates

Hence

For Side RT

  d=((2)4)2+((4)2)2Or, d=±72Or, d=72     (distance can't be negative so omit the negative root found)Or, d=8.5

Similarly

  RS=50Or, RS=7.07And ST=50Or, ST=7.07ST=7.07=RS & TR=8.50

Conclusion:

Hence, the length of R¯S¯,S¯T¯ is 7.07  and the length of R¯T¯ is  8.50

(b)

To determine

To classify:the triangle by its angles and sides.

(b)

Expert Solution
Check Mark

Answer to Problem 11STP

It is an isosceles triangle.

Explanation of Solution

From part a, the length of R¯S¯,S¯T¯ is 7.07  and the length of R¯T¯ is  8.50

Two sides are equal in the triangle.

Hence it is an isosceles triangle.

(b)

To determine

To find: perimeter of the triangle.

(b)

Expert Solution
Check Mark

Answer to Problem 11STP

The perimeter is 22.64 units.

Explanation of Solution

Calculation:

The perimeter of the triangle will be equal to the sum of all sides.

Thus perimeter (P)=RS+ST+TR

Substitute the values of R¯S¯,S¯T¯, and R¯T¯

  (P)=7.07+7.07+8.50=22.64

Conclusion:

Therefore, the perimeter is 22.64 units.

Chapter 10 Solutions

Pre-Algebra, Student Edition

Ch. 10.1 - Prob. 4CCYPCh. 10.1 - Prob. 4DCYPCh. 10.1 - Prob. 5CYPCh. 10.1 - Prob. 1CYUCh. 10.1 - Prob. 2CYUCh. 10.1 - Prob. 3CYUCh. 10.1 - Prob. 4CYUCh. 10.1 - Prob. 5CYUCh. 10.1 - Prob. 6CYUCh. 10.1 - Prob. 7CYUCh. 10.1 - Prob. 8CYUCh. 10.1 - Prob. 9CYUCh. 10.1 - Prob. 10CYUCh. 10.1 - Prob. 11PPSCh. 10.1 - Prob. 12PPSCh. 10.1 - Prob. 13PPSCh. 10.1 - Prob. 14PPSCh. 10.1 - Prob. 15PPSCh. 10.1 - Prob. 16PPSCh. 10.1 - Prob. 17PPSCh. 10.1 - Prob. 18PPSCh. 10.1 - Prob. 19PPSCh. 10.1 - Prob. 20PPSCh. 10.1 - Prob. 21PPSCh. 10.1 - Prob. 22PPSCh. 10.1 - Prob. 23PPSCh. 10.1 - Prob. 24PPSCh. 10.1 - Prob. 25PPSCh. 10.1 - Prob. 26PPSCh. 10.1 - Prob. 27PPSCh. 10.1 - Prob. 28PPSCh. 10.1 - Prob. 29PPSCh. 10.1 - Prob. 30PPSCh. 10.1 - Prob. 31PPSCh. 10.1 - Prob. 32PPSCh. 10.1 - Prob. 33PPSCh. 10.1 - Prob. 34PPSCh. 10.1 - Prob. 35PPSCh. 10.1 - Prob. 36PPSCh. 10.1 - Prob. 37PPSCh. 10.1 - Prob. 38PPSCh. 10.1 - Prob. 39PPSCh. 10.1 - Prob. 40HPCh. 10.1 - Prob. 41HPCh. 10.1 - Prob. 42HPCh. 10.1 - Prob. 43HPCh. 10.1 - 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Prob. 6PPSCh. 10.5 - Prob. 7PPSCh. 10.5 - Prob. 8PPSCh. 10.5 - Prob. 9PPSCh. 10.5 - Prob. 10PPSCh. 10.5 - Prob. 11PPSCh. 10.5 - Prob. 12PPSCh. 10.5 - Prob. 13PPSCh. 10.5 - Prob. 14PPSCh. 10.5 - Prob. 15PPSCh. 10.5 - Prob. 16PPSCh. 10.5 - Prob. 17PPSCh. 10.5 - Prob. 18PPSCh. 10.5 - Prob. 19PPSCh. 10.5 - Prob. 20PPSCh. 10.5 - Prob. 21PPSCh. 10.5 - Prob. 22PPSCh. 10.5 - Prob. 23PPSCh. 10.5 - Prob. 24PPSCh. 10.5 - Prob. 25PPSCh. 10.5 - Prob. 26PPSCh. 10.5 - Prob. 27HPCh. 10.5 - Prob. 28HPCh. 10.5 - Prob. 29HPCh. 10.5 - Prob. 30HPCh. 10.5 - Prob. 31HPCh. 10.5 - Prob. 32STPCh. 10.5 - Prob. 33STPCh. 10.5 - Prob. 34STPCh. 10.5 - Prob. 35STPCh. 10.5 - Prob. 36SRCh. 10.5 - Prob. 37SRCh. 10.5 - Prob. 38SRCh. 10.5 - Prob. 39SRCh. 10.5 - Prob. 40SCh. 10.5 - Prob. 41SCh. 10.5 - Prob. 42SCh. 10.6 - Prob. 1CYPCh. 10.6 - Prob. 2CYPCh. 10.6 - Prob. 3CYPCh. 10.6 - Prob. 1CYUCh. 10.6 - Prob. 2CYUCh. 10.6 - Prob. 3CYUCh. 10.6 - Prob. 4CYUCh. 10.6 - Prob. 5CYUCh. 10.6 - Prob. 6CYUCh. 10.6 - Prob. 7CYUCh. 10.6 - Prob. 8CYUCh. 10.6 - Prob. 9PPSCh. 10.6 - Prob. 10PPSCh. 10.6 - Prob. 11PPSCh. 10.6 - Prob. 12PPSCh. 10.6 - Prob. 13PPSCh. 10.6 - Prob. 14PPSCh. 10.6 - Prob. 15PPSCh. 10.6 - Prob. 16PPSCh. 10.6 - Prob. 17PPSCh. 10.6 - Prob. 18PPSCh. 10.6 - Prob. 19PPSCh. 10.6 - Prob. 20PPSCh. 10.6 - Prob. 21PPSCh. 10.6 - Prob. 22PPSCh. 10.6 - Prob. 23HPCh. 10.6 - Prob. 24HPCh. 10.6 - Prob. 25HPCh. 10.6 - Prob. 26HPCh. 10.6 - Prob. 27HPCh. 10.6 - Prob. 28STPCh. 10.6 - Prob. 29STPCh. 10.6 - Prob. 30STPCh. 10.6 - Prob. 31STPCh. 10.6 - Prob. 32SRCh. 10.6 - Prob. 33SRCh. 10.6 - Prob. 34SRCh. 10.6 - Prob. 35SRCh. 10.6 - Prob. 36SRCh. 10.6 - Prob. 37SRCh. 10.6 - Prob. 38SRCh. 10.6 - Prob. 39SRCh. 10.6 - Prob. 40SRCh. 10.6 - Prob. 41SCh. 10.6 - Prob. 42SCh. 10.6 - Prob. 43SCh. 10.6 - Prob. 44SCh. 10.6 - Prob. 45SCh. 10.6 - Prob. 46SCh. 10.6 - Prob. 47SCh. 10.6 - Prob. 48SCh. 10 - Prob. 1QCCh. 10 - Prob. 2QCCh. 10 - Prob. 3QCCh. 10 - Prob. 4QCCh. 10 - Prob. 5QCCh. 10 - Prob. 6QCCh. 10 - Prob. 7QCCh. 10 - Prob. 8QCCh. 10 - 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