The two atoms dipole-dipole interaction must be understand given the statements. Concept Introduction : Dipole-dipole interaction : This is intermolecular force that occurs between two polar molecules, for example slightly positive end of one polar molecule is attached to the slightly negative end of another polar molecule. Hence both molecules forces are weaker bonds, than hydrogen bonds stronger than London dispersion forces. Dissociation of dipole-dipole molecule : The ( H 2 O ) is a polar molecule it dissociated or align that the positive end of one molecule interactions with the negative end o another molecule. Covalent bond : The electron pairs are known as shared pairs or bonding and stable of attractive and repulsive forces between atoms, when they share electrons is known as covalent bond. To find: The intramolecular force should identified given the two molecules

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Chapter 10, Problem 111AE

Interpretation Introduction

Interpretation:

The two atoms dipole-dipole interaction must be understand given the statements.

Concept Introduction:

Dipole-dipole interaction: This is intermolecular force that occurs between two polar molecules, for example slightly positive end of one polar molecule is attached to the slightly negative end of another polar molecule. Hence both molecules forces are weaker bonds, than hydrogen bonds stronger than London dispersion forces.

Dissociation of dipole-dipole molecule: The ( $H2O$ ) is a polar molecule it dissociated or align that the positive end of one molecule interactions with the negative end o another molecule.

Covalent bond: The electron pairs are known as shared pairs or bonding and stable of attractive and repulsive forces between atoms, when they share electrons is known as covalent bond.

To find: The intramolecular force should identified given the two molecules

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Instructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br‍(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.

е. Д CH3 D*, D20

C. NaOMe, Br Br