9th Edition

ISBN: 8220100654428

Author: Jewett

Publisher: Cengage Learning US

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Textbook Question

Chapter 10, Problem 10.69AP

A shaft is turning at 65.0 rad/s at time t = 0. Thereafter, its angular acceleration is given by

α = − 10.0 − 5.00 t

where α is in rad/s² and t is in seconds. (a) Find the angular speed of the shaft at t = 3.00 s. (b) Through what angle does it turn between t = 0 and t = 3.00 s?

Definition Definition Rate of change of angular velocity. Angular acceleration indicates how fast the angular velocity changes over time. It is a vector quantity and has both magnitude and direction. Magnitude is represented by the length of the vector and direction is represented by the right-hand thumb rule. An angular acceleration vector will be always perpendicular to the plane of rotation. Angular acceleration is generally denoted by the Greek letter α and its SI unit is rad/s 2 .

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Chapter 10 Solutions

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A shaft is turning at 65.0 rad/s at time t = 0. Thereafter, its angular acceleration is given by α = − 10.0 − 5.00 t where α is in rad/s 2 and t is in seconds. (a) Find the angular speed of the shaft at t = 3.00 s. (b) Through what angle does it turn between t = 0 and t = 3.00 s?

Solution Summary: The author explains the angular speed of the shaft at t=3.0s, and its acceleration.

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Chapter 10 Solutions