Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Question
Chapter 10, Problem 10.6.1P
To determine
(a)
The maximum factored concentrated load that can be supported by using LRFD.
To determine
(b)
The maximum service concentrated load that can be supported by using ASD.
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The details of an end bearing stiffener are shown in Figure . The stiffener plates are 9⁄16-inch thick, and the web is 3⁄16-inch thick. The stiffeners are clipped 1⁄2 inch to provide clearance for the flange-to-web welds. All steel is A572 Grade 50. a. Use LRFD and determine the maximum factored concentrated load that can be supported. b. Use ASD and determine the maximum service concentrated load that can be supported.
The truss below is pin connected at A and E, and is acted on by the forces shown.
E
A
D
B
Identify all of the ZERO-FORCE MEMBERS by checking the boxes below (if there are
none, leave all boxes unchecked):
BF
AF
BC
BH
CD
EG
-GH
AB
CH
DG
DH
DE
-FH
Compute the maximum acceptable tensile SERVICE LOAD that may act on a
single tee section that is connected to a gusset plate using welds 12 inches long, as
shown in the figure. The service live load is three times the dead load. Use A992
steel. USE LRFD ONLY, no block shear will occur.
WT12 x 38
Longitudinal
welds
11.2 in? y = 3.0 in.
Given: Properties of WT12 × 38: Ag =
Use A992 Steel: F, = 50 ksi Fu = 65 ksi
bf = 8.99in.
%3D
%3D
LL = 3 DL
%3D
%3D
tw
y = centroidal distance
bf
C. What is the Governing Ultimate Tensile Capacity based on Net Fracture
Round your answer to 3 decimal places.
Chapter 10 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
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