Essentials Of Materials Science And Engineering, Si Edition
Essentials Of Materials Science And Engineering, Si Edition
4th Edition
ISBN: 9781337629157
Author: Donald R. Askeland, Wendelin J. Wright
Publisher: Cengage Learning
Question
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Chapter 10, Problem 10.42P
Interpretation Introduction

(a)

Interpretation:

The point representing 60 at% Bi at 250C is to be indicated on the Bi-Sb phase diagram along with the phases present and their relative amounts are to be determined.

Concept Introduction:

A matter can exist in different physical forms such as sold, liquid, gas, and plasma. These distinct physical forms are known as a Phase.

A phase has uniform physical and chemical properties and is bounded by a surface due to which two phases can be mechanically separated from each other.

Amount of each phase in at% is calculated using lever rule. At a particular temperature and composition, a tie line is drawn on the phase diagram of the solid solution between the solidus and liquidus curve. Then the portion of the lever opposite to the phase whose amount is to be calculated is considered in the formula used as:

  Phase at%=opposite arm of levertotal length of the tie line×100 ......... (1)

Interpretation Introduction

(b)

Interpretation:

The point representing 30 at% Bi at 500C is to be indicated on the Bi-Sb phase diagram along with the phases present and their relative amounts are to be determined.

Concept Introduction:

A matter can exist in different physical forms such as sold, liquid, gas, and plasma. These distinct physical forms are known as a Phase.

A phase has uniform physical and chemical properties and is bounded by a surface due to which two phases can be mechanically separated from each other.

Amount of each phase in at% is calculated using lever rule. At a particular temperature and composition, a tie line is drawn on the phase diagram of the solid solution between the solidus and liquidus curve. Then the portion of the lever opposite to the phase whose amount is to be calculated is considered in the formula used as:

  Phase at%=opposite arm of levertotal length of the tie line×100 ......... (1)

Interpretation Introduction

(c)

Interpretation:

The point representing 50 at% Bi at 600C is to be indicated on the Bi-Sb phase diagram along with the phases present and their relative amounts are to be determined.

Concept Introduction:

A matter can exist in different physical forms such as sold, liquid, gas, and plasma. These distinct physical forms are known as a Phase.

A phase has uniform physical and chemical properties and is bounded by a surface due to which two phases can be mechanically separated from each other.

Amount of each phase in at% is calculated using lever rule. At a particular temperature and composition, a tie line is drawn on the phase diagram of the solid solution between the solidus and liquidus curve. Then the portion of the lever opposite to the phase whose amount is to be calculated is considered in the formula used as:

  Phase at%=opposite arm of levertotal length of the tie line×100 ......... (1)

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Chapter 10 Solutions

Essentials Of Materials Science And Engineering, Si Edition

Ch. 10 - Prob. 10.11PCh. 10 - Prob. 10.12PCh. 10 - Prob. 10.13PCh. 10 - Prob. 10.14PCh. 10 - Prob. 10.15PCh. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Prob. 10.18PCh. 10 - Prob. 10.19PCh. 10 - Prob. 10.20PCh. 10 - Prob. 10.21PCh. 10 - Prob. 10.22PCh. 10 - Prob. 10.23PCh. 10 - Prob. 10.24PCh. 10 - Prob. 10.25PCh. 10 - Prob. 10.26PCh. 10 - Prob. 10.27PCh. 10 - Prob. 10.28PCh. 10 - Prob. 10.29PCh. 10 - Prob. 10.30PCh. 10 - Prob. 10.31PCh. 10 - Prob. 10.32PCh. 10 - Prob. 10.33PCh. 10 - Prob. 10.34PCh. 10 - Prob. 10.35PCh. 10 - Prob. 10.36PCh. 10 - Prob. 10.37PCh. 10 - Prob. 10.38PCh. 10 - Prob. 10.39PCh. 10 - Prob. 10.40PCh. 10 - Prob. 10.41PCh. 10 - Prob. 10.42PCh. 10 - Prob. 10.43PCh. 10 - Prob. 10.44PCh. 10 - Prob. 10.45PCh. 10 - Prob. 10.46PCh. 10 - Prob. 10.47PCh. 10 - Prob. 10.48PCh. 10 - Prob. 10.49PCh. 10 - Prob. 10.50PCh. 10 - Prob. 10.51PCh. 10 - Prob. 10.52PCh. 10 - Prob. 10.53PCh. 10 - Prob. 10.54PCh. 10 - Prob. 10.55PCh. 10 - Prob. 10.56PCh. 10 - Prob. 10.57PCh. 10 - Prob. 10.58PCh. 10 - Prob. 10.59PCh. 10 - Prob. 10.60PCh. 10 - Prob. 10.61PCh. 10 - Prob. 10.62PCh. 10 - Prob. 10.63PCh. 10 - Prob. 10.64PCh. 10 - Prob. 10.65PCh. 10 - Prob. 10.66PCh. 10 - Prob. 10.67PCh. 10 - Prob. 10.68PCh. 10 - Prob. 10.69PCh. 10 - Prob. 10.70PCh. 10 - Prob. 10.71PCh. 10 - Prob. 10.72PCh. 10 - Prob. 10.73PCh. 10 - Prob. 10.74PCh. 10 - Prob. 10.75PCh. 10 - Prob. 10.76PCh. 10 - Prob. 10.77PCh. 10 - Prob. 10.78PCh. 10 - Prob. 10.79PCh. 10 - Prob. 10.80PCh. 10 - Prob. 10.81PCh. 10 - Prob. 10.82PCh. 10 - Prob. 10.83PCh. 10 - Prob. 10.84PCh. 10 - Prob. 10.85PCh. 10 - Prob. 10.86PCh. 10 - Prob. 10.87PCh. 10 - Prob. 10.88DPCh. 10 - Prob. 10.89DPCh. 10 - Prob. 10.90DPCh. 10 - Prob. 10.91DPCh. 10 - Prob. 10.92CPCh. 10 - Prob. 10.93CPCh. 10 - Prob. 10.94CPCh. 10 - Prob. K10.1KP
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