EBK SYSTEM DYNAMICS
EBK SYSTEM DYNAMICS
3rd Edition
ISBN: 8220100254963
Author: Palm
Publisher: MCG
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Chapter 10, Problem 10.37P

For the designs found in part (a) of Problem 10.35, evaluate the steady-state error due to a unit-ramp command and due to a unit-ramp disturbance.

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A 15 cm-OD pipe is buried with its centerline 1.25 m below the surface of the ground [k of soil is 0.35 W/(m K)]. An oil having a density of 800 kg/m³ and a specific heat of 2.1 kJ/(kg K) flows in the pipe at 5.6 L/s. Assuming a ground surface temperature of 5°C and a pipe wall temperature of 95°C, estimate the length of pipe in which the oil temperature decreases by 5.5°C. + Tε = 5ºC Z= 1.25 m D= 15 cm 7p=95°C
Find the solution of the following Differential Equations 1) 4y+y=0, y(0)=2, y'(0) = 0. 2) y+y=0, y(0) = A, y'(0) = B. 3) "+2y'-8y=0, y(0)=1, y'(0)=8. 4) y"-2y-3y=0, y(0)=1, y'(0)=7. 5) y"-ky' =0, y(0)=2, y'(0) =k. 6) y+ky'-2k2y=0, y(0)=2, y'(0) = 2k. 7) y'+4y=0, y(0)=2.8 y+y-17sin(21) y(0)=-1. 9) y-y'-6y=0, y(0)=6. y'(0)=13. 10) y-y=0, 11) y"-4y+4y=0, y(0)=4, y'(0) = 0. y(0) = 2.1, y'(0)=3.9 12) y+2y+2y=0, y(0)=1, y'(0)=-3. 13) "+7y+12y=21e", y(0)=3.5, y'(0)=-10. 14) "+9y=10e", y(0)=0. y'(0) = 0. 15) y+3y+2.25y=91³ +64. y(0)=1, y'(0) = 31.5 16) "-6y+5y= 29 cos(21), y(0)=3.2, y'(0) = 6.2 17) y+2y+2y=0, y(0)=0, y'(0)=1. 18) y+2y+17y=0, y(0)=0, y'(0)=12. 19) y-4y+5y=0, y(0)-1, y'(0) 2. 20) 9y-6y+y=0. y(0)=3, y'(0)=1. 21) -2y+10y=0, y(0)=3, y'(0)=3. 22) 4y-4y+37y=0, (0) 3. y(0) 1.5 23) 4y-8y+5y=0, (0)-0, y(0) 1. 24) y+y+1.25y=0, y(0) 1. y'(0) -0.5 25) y+y=2 cos(1). y(0) 2. y'(0) = 0. 26) -4y+3y=0, (0)-3, y'(0) = 7. 27) y+2y+y=e", y(0)-0. y'(0) = 0. 29) 28) y+2y-3y-10sinh(2),…

Chapter 10 Solutions

EBK SYSTEM DYNAMICS

Ch. 10 - Prob. 10.15PCh. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Prob. 10.19PCh. 10 - Prob. 10.20PCh. 10 - Prob. 10.21PCh. 10 - Prob. 10.22PCh. 10 - Prob. 10.23PCh. 10 - Prob. 10.24PCh. 10 - Consider the PI speed control system shown in...Ch. 10 - Prob. 10.26PCh. 10 - Prob. 10.27PCh. 10 - Prob. 10.28PCh. 10 - Prob. 10.29PCh. 10 - Prob. 10.30PCh. 10 - Prob. 10.31PCh. 10 - Prob. 10.32PCh. 10 - Prob. 10.33PCh. 10 - Prob. 10.34PCh. 10 - Prob. 10.35PCh. 10 - Prob. 10.36PCh. 10 - For the designs found in part (a) of Problem...Ch. 10 - Prob. 10.39PCh. 10 - Prob. 10.40PCh. 10 - Prob. 10.41PCh. 10 - Prob. 10.44PCh. 10 - Prob. 10.45PCh. 10 - Prob. 10.46PCh. 10 - For the system shown in Figure 10.7.1, / = c = 1....Ch. 10 - Prob. 10.48PCh. 10 - Prob. 10.51PCh. 10 - Prob. 10.52PCh. 10 - Prob. 10.53PCh. 10 - Prob. 10.54PCh. 10 - Prob. 10.56PCh. 10 - Prob. 10.57PCh. 10 - Prob. 10.58PCh. 10 - Prob. 10.59PCh. 10 - Prob. 10.60PCh. 10 - Prob. 10.61PCh. 10 - Prob. 10.62PCh. 10 - Prob. 10.63PCh. 10 - Prob. 10.64PCh. 10 - Prob. 10.65PCh. 10 - Consider Example 10.6.3. Modify the diagram in...Ch. 10 - Prob. 10.67PCh. 10 - 10.68 Consider Example 10.6.4. Modify the diagram...Ch. 10 - 10.69 Figure P10.7 shows a system for controlling...Ch. 10 - A speed control system using an...Ch. 10 - Prob. 10.72PCh. 10 - Prob. 10.73PCh. 10 - Prob. 10.74PCh. 10 - Consider Example 10.7.4. Use the diagram in Figure...Ch. 10 - Prob. 10.76PCh. 10 - Refer to Figure 10.3.9, which show s a speed...Ch. 10 - For the system in Problem 10.77 part (a), create a...
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