EBK MATERIALS FOR CIVIL AND CONSTRUCTIO
4th Edition
ISBN: 8220102719569
Author: ZANIEWSKI
Publisher: PEARSON
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Question
Chapter 10, Problem 10.28QP
To determine
Write about the five different application conditions that are utilized to adjust the strength properties.
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For the purpose of designing wood structures, laboratory-measured strength properties are adjusted for application conditions. State five different applica-tion conditions that are used to adjust the strength properties.
please answer these two question
1.Explain the reason that flexural modulus of elasticity and compression test modulus of elasticity must be considered separately when both the flexural test and the parallel to grain compressive test caused normal stresses parallel to the grain of the wood.
2. Discuss the difference between isotropic and orthotropic materials for wood.
Calculate the modulus of elasticity of the wood specimen with the stress-strain relationship
shown in figure below.
25
20
15
10
0.1
0.2
0.3
0.4
0.5
STRAIN (%)
COMPRESSIVE STRESS PARALLEL TO
GRAINS (MPA)
Chapter 10 Solutions
EBK MATERIALS FOR CIVIL AND CONSTRUCTIO
Ch. 10 - What are the two main classes of wood? What is the...Ch. 10 - Prob. 10.2QPCh. 10 - Prob. 10.3QPCh. 10 - Discuss the anisotropic nature of wood. How does...Ch. 10 - Prob. 10.5QPCh. 10 - Prob. 10.6QPCh. 10 - Prob. 10.7QPCh. 10 - Prob. 10.8QPCh. 10 - Prob. 10.9QPCh. 10 - Prob. 10.10QP
Ch. 10 - Prob. 10.11QPCh. 10 - Prob. 10.12QPCh. 10 - Prob. 10.13QPCh. 10 - Prob. 10.14QPCh. 10 - Prob. 10.15QPCh. 10 - Prob. 10.16QPCh. 10 - Prob. 10.17QPCh. 10 - Prob. 10.18QPCh. 10 - Prob. 10.19QPCh. 10 - Prob. 10.20QPCh. 10 - Prob. 10.21QPCh. 10 - Prob. 10.22QPCh. 10 - Prob. 10.23QPCh. 10 - A wood specimen was prepared with actual...Ch. 10 - A pine wood specimen was prepared with actual...Ch. 10 - Prob. 10.26QPCh. 10 - Prob. 10.27QPCh. 10 - Prob. 10.28QPCh. 10 - Prob. 10.29QPCh. 10 - Prob. 10.30QPCh. 10 - Prob. 10.31QPCh. 10 - Prob. 10.32QPCh. 10 - Prob. 10.33QP
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Similar questions
- A pine wood specimen was prepared with actual dimensions of 50 mmx50 mm x 250 mm and grain parallel to its length. The deformation was measured over a gauge length of 200 mm. The specimen was subjected to compression parallel to the grain failure. The load- deformation results are shown in table below: Load (kN) Deformation (mm) 8.9 0.457 17.8 0.597 26.7 0.724 34.5 0.838 43 0.965 52.9 1.118 62.01 1.27 71.03 1.422 80.1 1.588 89 1.765 99.6 1.956 108 2.159 111.3 2.311 112 2.456 a. Using a computer spreadsheet program, plot the stress-strain relationship. b. Calculate the modulus of elasticity. С. What is the failure stress?arrow_forwardWhat are the two types of microscopic composites? Show the mechanism for strengthening of each type.arrow_forwardCompute the modulus of elasticity of the wood species whose stress–strainrelationship is shown in Figure 10.12, using both the SI and English units.Compare the results with the typical values shown in Table 1.1 in Chapter 1and comment about the results.arrow_forward
- if the stress at failure and bending is 7200 PSI for small, perfect samples of a certain species of wood, what is the allowable bending stress for a piece of lumber with defects that are judged to reduce the strength by 40%?arrow_forwardSteel modulus of elactisity is 29x10^6 psi what is concrete modulus of Elasticity in psi ?arrow_forward1. Discuss about Composite Materials and their different types, manufacturing techniques, and their applications in the construction and other manufacturing industries.arrow_forward
- A pine wood specimen was prepared with actual dimensions of 50 mm × 50 mm x 250 mm and grain parallel to its length. The deformation was meas- ured over a gauge length of 200 mm. The specimen was subjected to compres- sion parallel to the grain to failure. The load-deformation results are as shown in Table P10.25. TABLE P10.25 Load (Kn) Deformation (mm) 8.9 0.457 17.8 0.597 26.7 0.724 35.6 0.838 44.5 0.965 53.4 1.118 62.3 1.270 71.2 1.422 80.1 1.588 89.0 1.765 97.9 1.956 106.8 2.159 111.3 2.311 a. Using a computer spreadsheet program, plot the stress-strain relationship. b. Calculate the modulus of elasticity. c. What is the failure stress?arrow_forwardThe grains of wood in the board make an angle of 20° with the horizontal as shown. The board is subjected to an axial load of P = 300 N. (Figure 1) Part A Determine the normal stress that acts perpendicular to the grains. Express your answer to three significant figures and include the appropriate units. µA Value Units Submit Request Answer Figure < 1 of 1 Part B Determine the shear stress that acts parallel to the grains. Express your answer to three significant figures and include the appropriate units. HA -300 mm 160 mm Ta'y = Value Units 20° 25 mm1 Submit Request Answerarrow_forwardanswer quicklyarrow_forward
- The grains of wood in the board make an angle of 20° with the horizontal as shown. The board is subjected to an axial load of P = 250 N . (Figure 1) Part A Determine the normal stress that acts perpendicular to the grains. Express your answer to three significant figures and include the appropriate units. µA Value Units Figure 1 of 1 Submit Request Answer Part B 300 mm Determine the shear stress that acts parallel to the grains. 60 mm Express your answer to three significant figures and include the appropriate units. 20° 25 mm HẢ ? Value Units P Pearsonarrow_forwardc) Discuss the non-isotropic characteristics of wood.arrow_forwardDetermine the y-bar centroid of the composite figure shown. Where: y = 18mm and x = 9 mmShow your solution and round off if possiblearrow_forward
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