Elementary Principles of Chemical Processes 4e Binder Ready Version + WileyPLUS Registration Card (Wiley Plus Products)
Elementary Principles of Chemical Processes 4e Binder Ready Version + WileyPLUS Registration Card (Wiley Plus Products)
4th Edition
ISBN: 9781119231240
Author: Richard M. Felder
Publisher: Wiley (WileyPLUS Products)
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Chapter 10, Problem 10.25P

A liquid-phase chemical reaction with stoichiometry A ? B takes place in a semibatch reactor. The rate of consumption of A per unit volume of the reactor contents is given by the first-order rate expression (see Problem 10.19)

   r A [ m o l / ( L s ) ] = k C A

where CA(mol A/L) is the reactant concentration. The tank is initially empty. Beginning at a time t = 0, a solution containing A at a concentration CA0(mol A/L) is fed to the tank at a constant rate V ˙ ( L / s ) .

Write a differential balance on the total mass of the reactor contents. Assuming that the density of the contents always equals that of the feed stream, convert the balance into an equation for dV/dt, where V is the total volume of the contents, and provide an initial condition. Then write a differential mole balance on the reactant. A, letting NA(t) equal the total moles of A in the vessel, and provide an initial condition. Your equations should contain only the variables (VA, V, and t and the constants V ˙

  1. and CA0. (You should be able to eliminate CAas a variable.)
  2. Without attempting to integrate the equations, derive a formula for the steady-state value of NA.

  • Integrate the two equations to derive expressions for V(t) and NA(t), and then derive an expression for CA(t). Determine the asymptotic value of Naas t ? 8 and verify that the steady-state value obtained in Part (b) is correct. Briefly explain how it is possible for NAto reach a steady value when you keep adding A to the reactor and then give two reasons why this value would never be reached in a real reactor.
  • Determine the limiting value of CAas t ? 8 from your expressions for NA(t) and V(t). Then explain why your result makes sense in light of the results of Part (c).
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