Given the bond-dissociation energies: nitrogen-to-oxygen bond in N O , 631 k J m o l − 1 , H − H in H 2 , 436 k J m o l 1 ; N − H in H 2 O , 463 k J m o l − 1 ; N − H calculate Δ r H for the reaction below. 2 N O ( g ) + 5 H 2 ( g ) → 2 N H 3 ( g ) + 2 H 2 O ( g )
Given the bond-dissociation energies: nitrogen-to-oxygen bond in N O , 631 k J m o l − 1 , H − H in H 2 , 436 k J m o l 1 ; N − H in H 2 O , 463 k J m o l − 1 ; N − H calculate Δ r H for the reaction below. 2 N O ( g ) + 5 H 2 ( g ) → 2 N H 3 ( g ) + 2 H 2 O ( g )
Solution Summary: The author explains how the Delta_rH of the given reaction should be determined.
Given the bond-dissociation energies: nitrogen-to-oxygen bond in
N
O
,
631
k
J
m
o
l
−
1
,
H
−
H
in
H
2
,
436
k
J
m
o
l
1
;
N
−
H
in
H
2
O
,
463
k
J
m
o
l
−
1
;
N
−
H
calculate
Δ
r
H
for the reaction below.
2
N
O
(
g
)
+
5
H
2
(
g
)
→
2
N
H
3
(
g
)
+
2
H
2
O
(
g
)
Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.
Deducing the reactants of a Diels-Alder reaction
vn the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one
step, by moderately heating the reactants?
?
Δ
O
If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any
arrangement you like.
• If your answer is no, check the box under the drawing area instead.
Click and drag to start drawing a structure.
Product can't be made in one step.
Explanation
Check
Predict the major products of the following organic reaction:
Δ
?
Some important notes:
• Draw the major product, or products, of the reaction in the drawing area below.
• If there aren't any products, because no reaction will take place, check the box below the drawing area instead.
• Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are
enantiomers.
Explanation
Check
Click and drag to start drawing a structure.
L
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