Unit Operations of Chemical Engineering
7th Edition
ISBN: 9780072848236
Author: Warren McCabe, Julian C. Smith, Peter Harriott
Publisher: McGraw-Hill Companies, The
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Chapter 10, Problem 10.18P
Interpretation Introduction
Interpretation:
Cooling thermal profile is to be sketched for slab immersed in pool of flowing liquid.
Concept Introduction:
The fundamental concept of conduction-convection heat transfer is applied in unsteady state. The slab is assumed to be hotter and that is to be cooled by immersing in a stream of flowing liquid. It is evident that the heat stored inside the slab will dissipate into the surrounding fluid in such a way that the magnitude of fluid temperature depends upon exposure time.
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Only solve the specific enthalpies. Be thorough to the fullest for each calculation
Do question 9 please! Question 7 Is just there for reference!!
7) You are tasked with separating two proteins by ion exchange chromatography on a 30 cm long
column with an inner diameter of 2 cm. The resin has a diameter of 100 μm and a void fraction
of 0.3, and your mobile phase flows through the column at a rate of Q = 5 cm³/min. The Van
Deemter coefficients A, B, and C have been determined to be 0.0228 cm, 0.0036 cm²/min, and
0.00053 min, respectively, for both proteins. Protein A elutes from the column with an average
retention time of 27 min and standard deviation of 0.8 min. Protein B elutes from the column.
with an average retention time of 33.8 min and standard deviation of 1.0.
a) How many theoretical plates does the column contain?
b) What flow rate (Q) will give you the maximum resolution?
c) What is the minimum height of a theoretical plate for the system?
Chapter 10 Solutions
Unit Operations of Chemical Engineering
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- 1) Indicate whether each statement below is True or False: a) In extractions, small proteins usually end up in the heavy phase. b) In extractions, large proteins usually end up in the heavy phase. c) Tie line length on a phase diagram has no effect on protein partitioning. d) For extraction, we assume that each stage reaches equilibrium. e) Isotherms that are concave down lead to self-sharpening solute fronts in adsorption. f) When scaling up an adsorption unit, the LUB scales proportionally with adsorber length. g) For chromatography, separation efficiency increases when HETP increases. h) In size exclusion chromatography, smaller molecules elute from the column first. i) In hydrophobic interaction chromatography, very hydrophobic proteins elute in water. j) Molecules at very high concentrations elute from the column as a perfect Gaussian peak. k) In chromatography scale-up, resolution will increase as column diameter increases. 1) A good adsorbent typically has no porosity. m)…arrow_forwardChemical Engineering Use the psychrometric chart and demonstrate the linear interpolation method to obtain -0.52 KJ/KgDA. This is the enthalpy deviation. The exercise is uploaded below.arrow_forwardChemical Engineering Use the psychrometric chart. The remaining curves on the psychrometric chart are almost vertical and convex to the left, with labeled values (on Figure 8.4-1) of 0.05, 0.1, 0.2, and so on. (The units of these numbers arekJ/kg DA). Thesecurves are usedto determine theenthalpyof humid air that is not saturated. The procedure is as follows: (a) locate the point on the chart corresponding to air at its specified condition; (b) interpolate to estimate the enthalpy deviation at this point; (c) follow the constant wet-bulb temperature line to the enthalpy scale above the saturation curve, read the value on that scale, and add the enthalpy deviation to it. Also, you will see the exercise on the piece of paper.arrow_forward
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Author:Warren McCabe, Julian C. Smith, Peter Harriott
Publisher:McGraw-Hill Companies, The