Chapter 10, Problem 10.107CP

(a)

Interpretation Introduction

Interpretation:

The amount of lime required to remove one mole of $S{O}_2$ should be determined in grams.

Concept Introduction:

Moles: One mole is equivalent to the mass of the substance consists of same number of units equal to the atoms present in $\text{12}\text{g}$ of ${}^{\text{12}}\text{C}$.

The mole is calculated by using the following formula,

$\text{moles = }\frac{\text{given mass}}{\text{Molecular}\text{mass}}$

(b)

Interpretation Introduction

Interpretation:

The amount of lime required to remove one mole of $S{O}_2$ should be determined in kilograms.

Concept Introduction:

Moles: One mole is equivalent to the mass of the substance consists of same number of units equal to the atoms present in $\text{12}\text{g}$ of ${}^{\text{12}}\text{C}$.

The mole is calculated by using the following formula,

$\text{moles = }\frac{\text{given mass}}{\text{Molecular}\text{mass}}$

The grams is converted into kilograms by multiplying it with factor ${\text{10}}^{\text{-3}}$