You are given a solid mixture of NaNO 2 and NaCl and are asked to analyze it for the amount of NaNO 2 present. To do so, you allow the mixture to react with sulfamic acid, HSO 3 NH 2 , in water according to the equation NaNO 2 (aq) + HSO 3 NH 2 (aq) → NaHSO 4 (aq) + H 2 O( ℓ ) + N 2 (g) What is the weight percentage of NaNO 2 in 1.232 g of the solid mixture if reaction with sulfa-mic acid produces 295 mL of dry N 2 gas with a pressure of 713 mm Hg at 21.0 °C?
You are given a solid mixture of NaNO 2 and NaCl and are asked to analyze it for the amount of NaNO 2 present. To do so, you allow the mixture to react with sulfamic acid, HSO 3 NH 2 , in water according to the equation NaNO 2 (aq) + HSO 3 NH 2 (aq) → NaHSO 4 (aq) + H 2 O( ℓ ) + N 2 (g) What is the weight percentage of NaNO 2 in 1.232 g of the solid mixture if reaction with sulfa-mic acid produces 295 mL of dry N 2 gas with a pressure of 713 mm Hg at 21.0 °C?
Solution Summary: The author explains how the ideal gas equation can be obtained by combining Boyle's, Charles’s Law and Avogadro.
You are given a solid mixture of NaNO2 and NaCl and are asked to analyze it for the amount of NaNO2 present. To do so, you allow the mixture to react with sulfamic acid, HSO3NH2, in water according to the equation
NaNO2(aq) + HSO3NH2(aq) →
NaHSO4(aq) + H2O(ℓ) + N2(g)
What is the weight percentage of NaNO2 in 1.232 g of the solid mixture if reaction with sulfa-mic acid produces 295 mL of dry N2 gas with a pressure of 713 mm Hg at 21.0 °C?
10
5
4. These four 'H NMR spectra were recorded from different isomers with molecular formula
CsH,CIO. They all contain a carbonyl group. Determine the structure of the different isomers.
0
10
5
0
10
5
10
9
8
7
6
5
4
3.
1
0
9
10
10
66
9
0
10
9
10
5
1
8
7
6
5
3
2
-a
8
7
6
5
1
10
9
8
7
6
5
22
2
1
0
3
2
16
1
0
3
2 1
2
6
0
Use the expression below to
⚫ calculate its value and report it to the proper number of significant digits (you may need to
round your answer).
⚫ calculate the % error (or % relative error or % inherent error)
⚫ calculate the absolute error.
(20.54±0.02 × 0.254±0.003) / (3.21±0.05) =
Value:
% Error:
Absolute error: ± |
% (only 1 significant digit)
(only 1 significant digit)
In each case (more ductile, more brittle, more tough or resistant), indicate which parameter has a larger value.
parameter Elastic limit Tensile strength
more ductile
Strain at break Strength Elastic modulus
more fragile
more tough or resistant
General, Organic, and Biological Chemistry - 4th edition
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell