Chapter 1, Problem P7P

Explanation of Solution

The first present in the packet can be transmitted after generating all the bits required.

The time required to transmit the packet can be calculated by using the following expression.

$\text{Time}\text{required}\text{=}\frac{\text{Number}\text{of}\text{bits}}{\text{Transmission}\text{rate}\text{of}\text{the}\text{packet}}$

Note: $\text{1}\text{Byte}\text{=}\text{8}\text{bits}$ and $\text{1kbps}\text{=}{\text{10}}^{\text{3}}\text{bps}$

Substitute, “56×8” for “Number of bits” and “64×10³” for “Transmission rate of the packet” is given below:

The time required to transmit the first bit is $\frac{\text{56}\text{×}\text{8}}{\text{64}\text{×}{\text{10}}^{\text{3}}}\text{=}\text{7msec}$.

The time required to transmit the packet is $\frac{\text{56}\text{×}\text{8}}{\text{2}\text{×}{\text{10}}^{\text{6}}}\text{=}\text{224}\text{×}{\text{10}}^{\text{-6}}\text{sec}\text{(or)}\text{224μsec}$