Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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Expert Solution & Answer
Chapter 1, Problem P25P
a.
Explanation of Solution
The formula used for calculating the bandwidth-delay product is
The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is
Substitute, “20,000” for “m” and “2.5 ×108” for “s”
The propagation delay of the link is
b.
Explanation of Solution
The size of the file transmitted from Host A to Host B is 800,000 bits...
c.
Explanation of Solution
The bandwidth-delay produ...
d.
Explanation of Solution
“Yes” the width of the link is longer than the football field.
Reason:
The formula used for calculating the width of a bit present on the link is as follows
The formula used for calculating the bandwidth-delay product is
The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is
Substitute, “20,000” for “m” and “2.5 ×108” for “s”
The propagation delay of the link is
e.
Explanation of Solution
The expression used for calculating the width of a bit in the link and length of the required link in t...
Expert Solution & Answer
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Students have asked these similar questions
For a hierarchical carry look-ahead adder, GO can be written like below. Find the gate delay needed to obtain GO without fan-in and with a fan-in of 3 inputs.
GO=g7+p7g6+p7p6g5+p7p6p5g4+p7p6p5p4g3+p7p6p5p4p3g2+p7p6p5p4p3p2g1+p7p6p
5p4p3p2p1g0
Select one:
a.
O b.
GOO
B
B
GO without fan-in limitation will require 3 gate delays
GO with fan-in limitation of 3 will require 5 gate delays
GO without fan-in limitation will require 4 gate delays
• GO with fan-in of 3 will require 3 gate delays
C.
• GO without fan-in limitation will require 5 gate delays
GO with fan-in limitation of 3 will require 3 gate delays
O d.
GO without fan-in limitation will require 2 gate delays
GO with fan-in limitation of 3 will require 4 gate delays
1. Show that S₁ = S2 if and only if S₁ U S2 = S₁n S2.
2. Show that if S1 and S2 are finite sets with |S₁ = n and |S₂| = m, then
S₁ U S2 ≤n+m.
3. If language L is regular and is given by L ={awa : w = {a, b} *}
Then show that L² is regular.
Problem 3: Consider the two-link planar elbow manipulator shown below with link information: a₁ = 3,
a₂ = 3.
a2
S
3/0
Link | a | ai | di
ai
| di | 0i |
มา
02
21
02.
12
01
0 0 01
02
0
0
02
01
To
(a) Find the location of the end-effector P° if the joint angles are:
0₁ = 140°, 0₂ = 30°
(b) Find the values of joint variables 01, 02 if the robotic manipulator is commanded to reach the desired
location of Pº = [4.5, 3,0]. Notice there are possibly two sets of solutions.
(c) Also sketch the two poses of the robot for the computed joint variables.
Page 5 of 7
Chapter 1 Solutions
Computer Networking: A Top-Down Approach (7th Edition)
Ch. 1 - What is the difference between a host and an end...Ch. 1 - The word protocol is often used to describe...Ch. 1 - Why are standards important for protocols?Ch. 1 - Prob. R4RQCh. 1 - Prob. R5RQCh. 1 - Prob. R6RQCh. 1 - Prob. R7RQCh. 1 - Prob. R8RQCh. 1 - Prob. R9RQCh. 1 - Prob. R10RQ
Ch. 1 - Prob. R11RQCh. 1 - What advantage does a circuit-switched network...Ch. 1 - Prob. R13RQCh. 1 - Prob. R14RQCh. 1 - Prob. R15RQCh. 1 - Prob. R16RQCh. 1 - Prob. R17RQCh. 1 - Prob. R18RQCh. 1 - Suppose Host A wants to send a large file to Host...Ch. 1 - Prob. R20RQCh. 1 - Prob. R21RQCh. 1 - Prob. R22RQCh. 1 - What are the five layers in the Internet protocol...Ch. 1 - Prob. R24RQCh. 1 - Prob. R25RQCh. 1 - Prob. R26RQCh. 1 - Prob. R27RQCh. 1 - Prob. R28RQCh. 1 - Equation 1.1 gives a formula for the end-to-end...Ch. 1 - Prob. P3PCh. 1 - Prob. P4PCh. 1 - Prob. P5PCh. 1 - This elementary problem begins to explore...Ch. 1 - Prob. P7PCh. 1 - Suppose users share a 3 Mbps link. Also suppose...Ch. 1 - Prob. P9PCh. 1 - Prob. P10PCh. 1 - In the above problem, suppose R1 = R2 = R3 = R and...Ch. 1 - Prob. P13PCh. 1 - Consider the queuing delay in a router buffer. Let...Ch. 1 - Prob. P15PCh. 1 - Prob. P16PCh. 1 - Prob. P17PCh. 1 - Prob. P20PCh. 1 - Prob. P21PCh. 1 - Prob. P22PCh. 1 - Prob. P23PCh. 1 - Prob. P24PCh. 1 - Prob. P25PCh. 1 - Prob. P26PCh. 1 - Prob. P27PCh. 1 - Prob. P28PCh. 1 - Prob. P29PCh. 1 - Prob. P30PCh. 1 - Prob. P31PCh. 1 - Prob. P32PCh. 1 - Prob. P33PCh. 1 - Prob. P34P
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