Chapter 1, Problem P13P

a.

Explanation of Solution

The expression used for calculating the transmission time of each packet in terms of size of packet (L) and rate of link (R) is $\frac{\text{L}}{\text{R}}$  seconds.

The queuing delay for transmitting the first packet is $\frac{\text{0}}{\text{R}}=0$

The queuing delay for transmitting the second packet is $\frac{\text{L}}{\text{R}}$

The queuing delay for transmitting the third packet is $\frac{\text{2L}}{\text{R}}$

Similarly, the queuing delay for transmitting the N^th packet is $\frac{\text{(N-1)}\text{L}}{\text{R}}$

The average queuing delay for transmitting the N number of packets is

$\frac{(\text{0}\text{+}\frac{\text{L}}{\text{R}}\text{+}\frac{\text{2L}}{\text{R}}\text{+}\frac{\text{3L}}{\text{R}}\mathrm{..................}}{}$

b.

Explanation of Solution

The expression used for calculating the transmission time of each packet in terms of size of packet (L) and rate of link (R) is $\frac{\text{L}}{\text{R}}$  seconds.

Assume, the queuing delay for transmitting the first packet is $\frac{\text{0}\times \text{N}}{\text{R}}=0$

Then, the queuing delay for transmitting the second packet is $\frac{\text{NL}}{\text{R}}$ and the queuing delay for transmitting the third packet is $\frac{\text{2NL}}{\text{R}}$

Similarly, the queuing delay for transmitting the N^th packet is $\frac{\text{(N-1)}\text{NL}}{\text{R}}$

The average queuing delay for transmitting the N number of packets is

$\frac{(\text{0}\text{+}\frac{\text{NL}}{\text{R}}\text{+}\frac{\text{2NL}}{\text{R}}\text{+}\frac{\text{3NL}}{\text{R}}\mathrm{..................}}{}$