As mentioned on page 13, the MCO was lost because of a mix-up in the units used to calculate the force needed to correct its trajectory. Ground-based computers generated the forte correction file. On September 29, 1999, it was discovered that the fortes reported by the ground-based use in MCOnavigation software were by a factor of 4.45. The erroneous trajectory brought MCO 56 km above thesurface of Mars: the correct trajectory would have brought the MCO approximately 250 km above the surface. At 250 km, the NCO would have successfully entered the desired elliptic orbit. The data contained in the force correction files were delivered in lb-sec instead of the required Sl units of newton-sec for the MCO navigation software. The newton is the SI unit of force is described in Appendix B. The British Engineering (gravitational) system uses a pound (b) as a unit of force and ft / s 2 as a unit of acceleration. In turn. the pound is defined as the of on unit of mass at a caused by gravity 32.174ft / s 2 . The unit of mass this is the slug, which is 14.59 kg. Thus, BE unit of force = 1 pound = ( slug ) ( ft / s 2 ) Use thisinformation to confirm that BE unit of force = 4 .45×SI unit of force 1 pound = 4 .45 newton
As mentioned on page 13, the MCO was lost because of a mix-up in the units used to calculate the force needed to correct its trajectory. Ground-based computers generated the forte correction file. On September 29, 1999, it was discovered that the fortes reported by the ground-based use in MCOnavigation software were by a factor of 4.45. The erroneous trajectory brought MCO 56 km above thesurface of Mars: the correct trajectory would have brought the MCO approximately 250 km above the surface. At 250 km, the NCO would have successfully entered the desired elliptic orbit. The data contained in the force correction files were delivered in lb-sec instead of the required Sl units of newton-sec for the MCO navigation software. The newton is the SI unit of force is described in Appendix B. The British Engineering (gravitational) system uses a pound (b) as a unit of force and ft / s 2 as a unit of acceleration. In turn. the pound is defined as the of on unit of mass at a caused by gravity 32.174ft / s 2 . The unit of mass this is the slug, which is 14.59 kg. Thus, BE unit of force = 1 pound = ( slug ) ( ft / s 2 ) Use thisinformation to confirm that BE unit of force = 4 .45×SI unit of force 1 pound = 4 .45 newton
Solution Summary: The author explains that the scientific system of measurement is called the systeme internationale d’Unites and it is abbreviated SI.
As mentioned on page 13, the MCO was lost because of a mix-up in the units used to calculate the force needed to correct its trajectory. Ground-based computers generated the forte correction file. On September 29, 1999, it was discovered that the fortes reported by the ground-based use in MCOnavigation software were by a factor of 4.45. The erroneous trajectory brought MCO 56 km above thesurface of Mars: the correct trajectory would have brought the MCO approximately 250 km above the surface. At 250 km, the NCO would have successfully entered the desired elliptic orbit. The data contained in the force correction files were delivered in lb-sec instead of the required Sl units of newton-sec for the MCO navigation software. The newton is the SI unit of force is described in Appendix B. The British Engineering (gravitational) system uses a pound (b) as a unit of force and ft / s2 as a unit of acceleration. In turn. the pound is defined as the of on unit of mass at a caused by gravity 32.174ft / s2. The unit of mass this is the slug, which is 14.59 kg. Thus,
BE unit of force = 1 pound =
(
slug
)
(
ft / s
2
)
Use thisinformation to confirm that
BE unit of force = 4
.45×SI unit of force
Please help me find the 1/Time, Log [I^-] Log [S2O8^2-], Log(time) on the data table. With calculation steps. And the average for runs 1a-1b. Please help me thanks in advance. Will up vote!
Q1: Answer the questions for the reaction below:
..!! Br
OH
a) Predict the product(s) of the reaction.
b) Is the substrate optically active? Are the product(s) optically active as a mix?
c) Draw the curved arrow mechanism for the reaction.
d) What happens to the SN1 reaction rate in each of these instances:
1. Change the substrate to
Br
"CI
2. Change the substrate to
3. Change the solvent from 100% CH3CH2OH to 10% CH3CH2OH + 90% DMF
4. Increase the substrate concentration by 3-fold.
Experiment 27 hates & Mechanisms of Reations
Method I visual Clock Reaction
A. Concentration effects on reaction Rates
Iodine
Run [I] mol/L [S₂082] | Time
mo/L
(SCC)
0.04 54.7
Log
1/ Time Temp Log [ ] 13,20] (time)
/ [I] 199
20.06
23.0
30.04 0.04
0.04 80.0
22.8
45
40.02
0.04 79.0
21.6
50.08
0.03 51.0
22.4
60-080-02 95.0
23.4
7 0.08
0-01 1970
23.4
8 0.08 0.04 16.1
22.6
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
What are CHNOPS? These Chemical Elements = 98% of Life | Biology | Biochemistry; Author: Socratica;https://www.youtube.com/watch?v=w90wFlR53VM;License: Standard YouTube License, CC-BY