Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN: 9781305960961
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 1, Problem 8P
How long does it take light to cross the diameter of our Milky Way Galaxy?
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
The nearest star to our sun is Proxima Centauri, at a distance of 4.3 light-years from the Sun. A light-year is the distance that light travels in one year (365 days). How far away, in kilometers, is Proxima Centauri from the Sun?Express your answer using two significant figures.
question 1: parts A, B, and C please
The moon is 1.3 light-seconds away. Imagine you are standing at the Canadian Space Agency headquarters in St. Hubert, Quebec and you bounce a 755 MHz radio signal off the moon (the moon acts like a mirror, reflecting the signal, such that it comes back to you). How long will it take for that radio signal to get back to you on earth? Answer in seconds with one decimal place.
Chapter 1 Solutions
Horizons: Exploring the Universe (MindTap Course List)
Ch. 1 - What is the largest dimension of which you have...Ch. 1 - What is the difference between our Solar System,...Ch. 1 - Why are light-years more convenient than miles,...Ch. 1 - Why is it difficult to detect planets orbiting...Ch. 1 - Prob. 5RQCh. 1 - What is the difference between the Milky Way and...Ch. 1 - What are the largest known structures in the...Ch. 1 - Prob. 8RQCh. 1 - How Do We Know? How does the scientific method...Ch. 1 - You and three of your friends have won an...
Ch. 1 - Think back to the last time you got a new phone...Ch. 1 - The diameter of Earth across the equator is 7928...Ch. 1 - The diameter of the Moon across its equator is...Ch. 1 - One astronomical unit is about 1.50108 km. Explain...Ch. 1 - Venus orbits 0.72 AU from the Sun. What is that...Ch. 1 - Light from the Sun takes 8 minutes to reach Earth....Ch. 1 - The Sun is almost 400 times farther from Earth...Ch. 1 - If the speed of light is 3.00105 km/s. how many...Ch. 1 - How long does it take light to cross the diameter...Ch. 1 - The nearest large galaxy to our n is about 2.5...Ch. 1 - How many galaxies like our own would it take Laid...Ch. 1 - In Figure 1-4, the division between daylight and...Ch. 1 - Prob. 2LTLCh. 1 - Prob. 3LTLCh. 1 - Prob. 4LTL
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The distance from the Sun to the nearest star is about 4 1016 m. The Milky Way galaxy (Fig. P1.31) is roughly a disk of diameter 1021 in and thickness 1019 m. Find the order of magnitude of the number of stars in the Milky Way. Assume the distance between the Sun and our nearest neighbor is typical. Figure P1.31 The Milky Way galaxy.arrow_forwardA scientist, using a telescope, sees arcs of light around a galaxy. In 3–5 sentences, explain the cause of the arcs of light.arrow_forwardOn a 1-to-10^19 scale our Milky Way galaxy would just about fit on a soccer field. On this scale, how far is the distance from the sun to alpha centauri (one of the closest stars to the sun, at a distance of 4.4 light years).arrow_forward
- Earth is about 150 million kilometers from the Sun (1 Astronomical Unit, or AU), and the apparent brightness of the Sun in our sky is about 1300 watts/m2. Using these two facts and the inverse square law for light, determine the apparent brightness that we would measure for the Sun if we were located at the following positions. a) At the orbit of Jupiter (780 million km from the Sun).arrow_forwardEarth is about 150 million kilometers from the Sun (1 Astronomical Unit, or AU), and the apparent brightness of the Sun in our sky is about 1300 watts/m2. Using these two facts and the inverse square law for light, determine the apparent brightness that we would measure for the Sun if we were located at the following positions. a) At the orbit of Venus (67 million km from the Sun)arrow_forwardRecall that Hubble’s Law is given by V=HR; this means that H has units of inverse seconds (1/sec). A convenient laboratory set of units is to give H in km per sec per megaparsec. A parsec is 3.26 light years and the speed of light is 3 X 105 km/sec. Use 3.156 X 107 sec/yr. The first data off the then new Hubble Space telescope suggested a value of H equal to 108 km per sec per megaparsec. What is H in inverse seconds? Hint divide by the number of km in a megaparsec.arrow_forward
- The Sun and the planets of the solar system are located in a spiral galaxy , called the Milky Way . Which numbered area on the model best represents the location of the Sun in this galaxy ?arrow_forwardOur galaxy is approximately 100,000 light years in diameter and 2,000 light years thick through the plane of the galaxy. If we were to compare the ratio of the diameter galaxy and its thickness to the ratio of the diameter of a CD and its thickness (CD has a diameter of 12 cm and thickness of 0.6 mm), what would be the factor differentiating those ratios? Put differently, if the galaxy were scaled down to the diameter of a CD, how many times thicker or thinner would the galaxy be than the CD? (For example if it would be twice as thick, you would answer 2 and if it were twice as thin you would answer 0.5 (aka 1/2))arrow_forwardAn astronomical unit (AU) is defined as the average distance between the solar system and Alpha Centauri the Earth and the Moon the Milky Way Galaxy and the Andromeda Galaxy the Earth and the Sunarrow_forward
- The distance between the Earth and the Sun is ca. 150,000,000 km. If the Sun suddenly stopped shining, how long will it take before we find out?arrow_forwardThe intensity of light from a central source varies inversely as the square of the distance. If you lived on a planet only half as far from the Sun as our Earth, how would Sun’s light intensity compare with that on Earth? How about a planet 10 times farther away than Earth?arrow_forwardYou travel to another star system and meet some aliens. They say there are 146 constellations in the sky and not 88? Why would they possibly say that?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Stars and Galaxies (MindTap Course List)PhysicsISBN:9781337399944Author:Michael A. SeedsPublisher:Cengage LearningAstronomyPhysicsISBN:9781938168284Author:Andrew Fraknoi; David Morrison; Sidney C. WolffPublisher:OpenStaxStars and GalaxiesPhysicsISBN:9781305120785Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning
- Foundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Stars and Galaxies (MindTap Course List)
Physics
ISBN:9781337399944
Author:Michael A. Seeds
Publisher:Cengage Learning
Astronomy
Physics
ISBN:9781938168284
Author:Andrew Fraknoi; David Morrison; Sidney C. Wolff
Publisher:OpenStax
Stars and Galaxies
Physics
ISBN:9781305120785
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Foundations of Astronomy (MindTap Course List)
Physics
ISBN:9781337399920
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
General Relativity: The Curvature of Spacetime; Author: Professor Dave Explains;https://www.youtube.com/watch?v=R7V3koyL7Mc;License: Standard YouTube License, CC-BY