Organic Chemistry - Standalone book
10th Edition
ISBN: 9780073511214
Author: Francis A Carey Dr., Robert M. Giuliano
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 1, Problem 72DSP
Interpretation Introduction
Interpretation:
The Lewis formula that is a constitutional isomer of formamide is to be determined.
Concept introduction:
Compounds having the same molecular formula are called isomers.
Constitutional isomers are the compounds having same molecular formula but they differ in the connectivity of atoms present in the compounds.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
1) Choose a period from the Periodic Table.
2) Identify the period by its number and indicate the first atom and the last one, indicating to which group each one corresponds.
3) Write the electronic configuration of each representative element of the chosen period.
4) Determine the valence electrons of each of these elements.
5) Compare the number of valence electrons of the first and last element of the period.
6) Compare the electronic configurations. Point out similarities and differences in a synthesis of what was observed.
Unshared, or lone, electron pairs play an important role in determining the chermical and physical properties of organic compounds. Thus, it is important
to know which atoms carry unshared pairs.
Use the structural formulas below to determine the number of unshared pairs at each designated atom.
Be sure your answers are consistent with the formal charges on the formulas.
The number of unshared pairs at atom a is
The number of unshared pairs at atom b is
HyC
CH
The number of unshared pairs at atom e is
The number of unshared pairs at atom a is
The number of unshared pairs at atom b is
HC
CH
The number of unshared pairs at atom e is
The bond lengths of ethane, ethene, and ethyne were determined, and a graph of the C-H bond length vs. % s-character of the C hybrid orbital was made.
Comment on the observed trend, additionally. How would this trend change if C-H bond energy vs. % s-character of the C hybrid orbital was graphed? Which hydrocarbon has the strongest carbon-carbon bond?
Chapter 1 Solutions
Organic Chemistry - Standalone book
Ch. 1.1 - How many electrons does carbon have? How many are...Ch. 1.1 - Referring to the periodic table as needed, write...Ch. 1.2 - Species that have the same number of electrons are...Ch. 1.2 - Which of the following ions possess a noble gas...Ch. 1.2 - Prob. 5PCh. 1.3 - Prob. 6PCh. 1.3 - Problem 1.7 All of the hydrogens are bonded to...Ch. 1.4 - Problem 1.8 In which of the compounds...Ch. 1.4 - Indicate the direction of the dipole for the...Ch. 1.5 - Prob. 10P
Ch. 1.5 - The following inorganic species will be...Ch. 1.5 - Prob. 12PCh. 1.6 - Prob. 13PCh. 1.6 - Problem 1.14 Nitrosomethane and formaldoxime both...Ch. 1.6 - Prob. 15PCh. 1.7 - All of the bonds in the carbonate ion (CO32-) are...Ch. 1.7 - Prob. 17PCh. 1.8 - Prob. 18PCh. 1.8 - Prob. 19PCh. 1.9 - Sodium borohydride, NaBH4, has an ionic bond...Ch. 1.9 - Prob. 21PCh. 1.10 - Which of the following compounds would you expect...Ch. 1.11 - Using the curved arrow to guide your reasoning,...Ch. 1.11 - Prob. 24PCh. 1.11 - Prob. 25PCh. 1.12 - Prob. 26PCh. 1.12 - Prob. 27PCh. 1.12 - Prob. 28PCh. 1.12 - Prob. 29PCh. 1.12 - Prob. 30PCh. 1.13 - Which is the stronger acid, H2O or H2S? Which is...Ch. 1.13 - Prob. 32PCh. 1.13 - Prob. 33PCh. 1.13 - Hypochlorous and hypobromous acid (HOClandHOBr)...Ch. 1.13 - Prob. 35PCh. 1.13 - Prob. 36PCh. 1.14 - What is the equilibrium constant for the following...Ch. 1.14 - Prob. 38PCh. 1.14 - Prob. 39PCh. 1.15 - Write an equation for the Lewis acid/Lewis base...Ch. 1 - Write a Lewis formula for each of the following...Ch. 1 - Prob. 42PCh. 1 - Write structural formulas for all the...Ch. 1 - Prob. 44PCh. 1 - Expand the following structural representations so...Ch. 1 - Each of the following species will be encountered...Ch. 1 - Consider Lewis formulas A, B, and C: H2 C -NN:...Ch. 1 - Prob. 48PCh. 1 - Prob. 49PCh. 1 - Prob. 50PCh. 1 - Prob. 51PCh. 1 - Prob. 52PCh. 1 - Prob. 53PCh. 1 - Prob. 54PCh. 1 - Which compound in each of the following pairs...Ch. 1 - With a pKa of 11.6, hydrogen peroxide is a...Ch. 1 - The structure of montelukast, an antiasthma drug,...Ch. 1 - One acid has a pKa of 2, the other has a pKa of 8....Ch. 1 - Calculate Ka for each of the following acids,...Ch. 1 - Rank the following in order of decreasing acidity....Ch. 1 - Rank the following in order of decreasing...Ch. 1 - Consider 1.0 M aqueous solutions of each of the...Ch. 1 - Prob. 63PCh. 1 - Prob. 64PCh. 1 - Prob. 65PCh. 1 - Prob. 66PCh. 1 - Prob. 67PCh. 1 - Prob. 68PCh. 1 - Amide Lewis Structural Formulas Lewis formulas are...Ch. 1 - Amide Lewis Structural Formulas Lewis formulas are...Ch. 1 - Amide Lewis Structural Formulas Lewis formulas are...Ch. 1 - Prob. 72DSPCh. 1 - Amide Lewis Structural Formulas Lewis formulas are...Ch. 1 - Amide Lewis Structural Formulas Lewis formulas are...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Draw the Lewis dot structure of the conjugate base of cyclopentane by assuming all the atoms in the molecule obey the octet rule. Show all lone pairs and formal charges. Do no draw resonance structures.arrow_forwardFour major contributing resonance structures are possible for the given cation, which is the intermediate o complex of an electrophilic aromatic substitution involving phenol and bromine. Two structures are given but are incomplete. Complete the given structures by adding nonbonding electrons and formal charges. Draw the remaining structures (in any order), including nonbonding electrons and formal charges. Complete structure A. Complete structure B. : 0 H :0- Br : Brarrow_forwardNonearrow_forward
- Ethanol, , is a compound in which the formal charge on all the atoms is zero. Under certain conditions the bond can be broken so that both electrons remain with the oxygen atom. The products are In this structure the oxygen owns one electron from shared pair and two electrons from each of unshared pairs. The total number of electrons belonging to oxygen is Oxygen is a Group element. The formal charge on the oxygen atom is . The correct Lewis structure for the ethoxide ion is Note that the other fragment, the proton, leaves with a formal charge of +1.arrow_forwardGive clear detailed Solution with explanation needed..please avoid handwritten Solutionarrow_forwardCaffeine is an aromatic compound. Using resonance structures, show how the sixmember ring can be drawn in its "benzoid" form. Indicate the hybridization of each nitrogen atom and specify the hybridization of the orbital occupied by each of the lone pairs.Write all possible reasonable resonance structures for the following compounds. Label the major and minor contributors to each resonance hybrid. N : Z— N:arrow_forward
- Write the net ionic chemical equilibrium that gets established triethylamine, is dissolved in water. Use full lewis structures and show all lone electron pairs for reactants and products. Above each reaction arrow, write whether the reaction represents a Ka or Kb reaction.arrow_forward[Review Topics) [References] Unshared, or lone, electron pairs play an important role in determining the chemical and physical properties of organic compounds. Thus, it is important to know which atoms carry unshared pairs. Use the structural formulas below to determine the number of unshared pairs at each designated atom. Be sure your answers are consistent with the formal charges on the formulas. The number of unshared pairs at atom a is H,C- The number of unshared pairs at atom b is CCH2 The number of unshared pairs at atom c is e. The number of unshared pairs at atom a is H3C The number of unshared pairs at atomb is H3C The number of unshared pairs at atom c is Submit Answer Retry Entire Group 9 more group attempts remaining Previous Next étv 18 MacBook Air 888 F9 5 6 8 %3D Y %3D F н J 34 command option .... Varrow_forwardUne or more valid answers. Explain the answers. The localization or resonance energy: a) Justify the increased stability of molecules that have unlocated electrons b) It is a consequence of the mobility of the electrons that form the “sigma” bonds c) It occurs in compounds with conjugated double bonds, but not in aromatic compounds d) It is shown by the experimental values of the enthalpies of formation.arrow_forward
- Valence displayed by the underlined atoms.arrow_forwardThe molecule shown on the right in the example in the right column is the amino acid histidine, and the five-membered ring is known as aromatic. An aromatic ring has 2, 6, 10, 14, etc., electrons placed in 2p orbitals around a ring. Indicate which of the following statements must therefore be true. 1. There are a total of six electrons in the pi system (defined as electrons in 2p orbitals), including the lone pair on the ring N that is not circled. 2. There are a total of six electrons in the pi system, including the lone pair on the ring N atom that is circled. 3. The lone pair on the ring N atom that is not circled resides in an sp2 orbital on an sp2 hybridized nitrogen atom. 4. Statements 2 and 3 are both truearrow_forwardCompare the bonding in formic acid (HCOOH) with that in its conjugate base formate ion (HCOO). Each molecule has a central carbon atom bonded to the two oxygen atoms and to a hydrogen atom. Draw Lewis diagrams, determine the steric numbers and hybridization of the central carbon atom, and give the molecular geometries. How do the orbitals differ in formic acid and the formate molecular ion? The bond lengths of the CO bonds in HCOOH are 1.23 (for the bond to the lone oxygen) and 1.36 (for the bond to the oxygen with a hydrogen atom attached). In what range of lengths do you predict the CO bond length in the formate ion to lie?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage LearningOrganic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
Principles of Modern Chemistry
Chemistry
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:Cengage Learning
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Introductory Chemistry: An Active Learning Approa...
Chemistry
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Cengage Learning
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
General Chemistry | Acids & Bases; Author: Ninja Nerd;https://www.youtube.com/watch?v=AOr_5tbgfQ0;License: Standard YouTube License, CC-BY