The Analysis of Biological Data
2nd Edition
ISBN: 9781936221486
Author: Michael C. Whitlock, Dolph Schluter
Publisher: W. H. Freeman
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Chapter 1, Problem 6PP
a)
To determine
To explain: the reason that the 80 neurons constitute a random sample.
b)
To determine
To explain: Consequences of the 80 measurements on the estimation of the measurement in the monkey population.
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Students have asked these similar questions
32. Consider a normally distributed population with mean μ = 80
and standard deviation σ = 14.
a.
Construct the centerline and the upper and lower control
limits for the chart if samples of size 5 are used.
b. Repeat the analysis with samples of size 10.
2080 101
c. Discuss the effect of the sample size on the control limits.
Consider the following hypothesis test.
The following results are for two independent samples taken from the two populations.
Sample 1
Sample 2
n 1 = 80
n 2 = 70
x 1 = 104
x 2 = 106
σ 1 = 8.4
σ 2 = 7.6
What is the value of the test statistic? If required enter negative values as negative numbers (to 2 decimals).
What is the p-value (to 4 decimals)? Use z-table.
With = .05, what is your hypothesis testing conclusion?
Periodically, Merrill Lynch customers are asked to evaluate Merrill Lynch financial consultants and services (2000 Merrill Lynch Client Satisfaction Survey). Higher ratings on the client satisfaction survey indicate better service with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use = .05 and test to see whether the consultant with more experience has the higher population mean service rating.
Consultant A
Consultant B
= 16
= 10
= 6.82
= 6.25
= .64
= .75
State the null and alternative hypotheses.H0: 1 - 2 Ha: 1 - 2
Compute the value of the test statistic (to 2 decimals).
What is the p-value?The p-value is
What is your conclusion?
Chapter 1 Solutions
The Analysis of Biological Data
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