Interpretation Introduction To determine: Mass of carbon dioxide present in the room of given dimensions. Explanation Given Concentration of the carbon dioxide = 48 μg / m 3 Length of the room = 10.6 ft Breadth of the room = 14.8 ft Length of the room = 20.5 ft Formula The volume of the room is calculated using the formula, Volume = Length × Breadth × Height Substitute the given values of length, breadth and height in the above expression, Volume = ( 10 .6 × 14 .8 × 20 .5 ) ft 3 = 3216.04 ft 3 The conversion of 1 ft 3 into cubic meters ( m 3 ) is done as, 1 ft 3 = 0.0283 m 3 Hence, The conversion of 3216.04 ft 3 into cubic meters ( m 3 ) is done as, 3216.04 ft 3 = ( 3216.04 × 0.028 ) m 3 = 90

Chemistry: The Central Science (14th Edition)

14th Edition

ISBN: 9780134414232

Author: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Catherine Murphy, Patrick Woodward, Matthew E. Stoltzfus

Publisher: PEARSON

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Chapter 1, Problem 62E

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To determine: Mass of carbon dioxide present in the room of given dimensions.

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Chapter 1, Problem 61E

Chapter 1, Problem 63E

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Chemistry: The Central Science (14th Edition)

Ch. 1.2 - Practice Exercise 1 Which of the following is the...Ch. 1.2 - Aspirin is composed of 60.0% carbon, 4.5%...Ch. 1.5 - Practice Exercise 1 Which of the following weights...Ch. 1.5 - Practice Exercise 2 How many picometers are there...Ch. 1.5 - Practice Exercise 1 Using Wolfram Alpha...Ch. 1.5 - Practice Exercise 2 Ethylene glycol, the major...Ch. 1.5 - Practice Exercise 1 Platinum, Pt. is one of the...Ch. 1.5 - Practice Exercise 2 Calculate the density of a...Ch. 1.5 - Which of the following objects has the greatest...Ch. 1.5 - Prob. 1.5.2PE

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