Explanation Given information: The dimension of the sample is 10cm × 10 cm and 0 .5 cm thickness . Temperature in the inner and outer surface of the glass is 82 ° C and 74 ° C , respectively. Electric power drawn by heater is 25W . Calculations: Rate of heat transfer ( Q ) = kA Δ T L Where, ( Δ T ) = Temperature difference= ( 82 − 74 ) = 8 ( A ) = Surface area of heat transfer of sample=0 .1m × 0 .1m=0 .01m 2 ( L ) = Thickness of the sample=0

HEAT&MASS TRANSF. (LL) W/CONNECT<CUSTOM>

6th Edition

ISBN: 9781266141652

Author: CENGEL

Publisher: MCG

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Question

Chapter 1, Problem 56P

To determine

The thermal conductivity of the sample.

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Chapter 1, Problem 55P

Chapter 1, Problem 57P

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Chapter 1 Solutions

HEAT&MASS TRANSF. (LL) W/CONNECT<CUSTOM>

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