(a) Interpretation: The boiling point of water in A 0 if melting point of ammonia is 0 A 0 or − 77.75 C 0 and boiling point of ammonia is 100 A 0 or - 33.35 C 0 needs to be determined. Concept introduction: The conversion factor required to determine the results in different or desired scale by equivalizing the different units. The temperature of the sample at given scale degree M can be identified as follows: ( T calculated ( in o A ) – T lower ( in o A ) ) ( T higher ( in o A ) – T lower ( in o A ) ) = ( T calculated ( in o C ) – T lower ( in o C ) ) ( T higher ( in o C ) – T lower ( in o C ) )

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Answer 1

Question

Chapter 1, Problem 46E

Interpretation Introduction

(a)

Interpretation:

The boiling point of water in A⁰ if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰ needs to be determined.

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Interpretation Introduction

(b)

Interpretation:

The absolute zero temperature in A⁰ needs to be determined, if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

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a. What is the eluent used in the column chromatography here (a “silica plug filtration” is essentially a very short column)? b. The spectroscopy of compound 5b is described in the second half of this excerpt, including 1H-NMR and 13C-NMR (which you will learn about in CHEM 2412L), MS (which you will learn about later in CHEM 2411L) and IR. One of the IR signals is at 3530 cm-1. What functional group does this indicate might be present in compound 5b?

Steps and explanations. Also provide, if possible, ways to adress this kind of problems in general.

a. The first three lines of this procedure describe the reaction used to make compound 5b. In the fourth line, hexane and sodium bicarbonate are added. What organic lab technique is being used here? b. What is the purpose of the Na2SO4? c. What equipment would you use to “concentrate [a solution] under reduced pressure”?

Answer 2

Question

Chapter 1, Problem 46E

Interpretation Introduction

(a)

Interpretation:

The boiling point of water in A⁰ if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰ needs to be determined.

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Interpretation Introduction

(b)

Interpretation:

The absolute zero temperature in A⁰ needs to be determined, if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Expert Solution & Answer

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Answer 3

Question

Chapter 1, Problem 46E

Interpretation Introduction

(a)

Interpretation:

The boiling point of water in A⁰ if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰ needs to be determined.

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Interpretation Introduction

(b)

Interpretation:

The absolute zero temperature in A⁰ needs to be determined, if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Expert Solution & Answer

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Answer 4

Question

Chapter 1, Problem 46E

Interpretation Introduction

(a)

Interpretation:

The boiling point of water in A⁰ if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰ needs to be determined.

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Interpretation Introduction

(b)

Interpretation:

The absolute zero temperature in A⁰ needs to be determined, if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

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Answer 5

Chapter 1, Problem 46E

Interpretation Introduction

(a)

Interpretation:

The boiling point of water in A⁰ if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰ needs to be determined.

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Interpretation Introduction

(b)

Interpretation:

The absolute zero temperature in A⁰ needs to be determined, if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Answer 6

Chapter 1, Problem 46E

Interpretation Introduction

(a)

Interpretation:

The boiling point of water in A⁰ if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰ needs to be determined.

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Answer 7

Chapter 1, Problem 46E

Interpretation Introduction

(a)

Interpretation:

The boiling point of water in A⁰ if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰ needs to be determined.

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Answer 8

Interpretation Introduction

(b)

Interpretation:

The absolute zero temperature in A⁰ needs to be determined, if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Answer 9

Interpretation Introduction

(b)

Interpretation:

The absolute zero temperature in A⁰ needs to be determined, if melting point of ammonia is 0 A⁰ or − 77.75 C⁰ and boiling point of ammonia is 100 A⁰ or - 33.35 C⁰

Concept introduction:

The conversion factor required to determine the results in different or desired scale by equivalizing the different units.

The temperature of the sample at given scale degree M can be identified as follows:

(T calculated ( in o A) – T lower ( in o A))(T higher( in o A) – T lower ( in o A)) = (T calculated( in o C) – T lower( in o C)) (T higher( in o C) – T lower( in o C))

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

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Answer 13

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Solution Summary: The author explains the conversion factor required to determine the results in different or desired scale by equivalizing the different units.

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Chapter 1 Solutions