Explanation Given: Mass of hydrogen = 1.50 g Mass of oxygen = 12.0 g The problem is based on moles and limiting reagent. Balance Chemical equation to form water vapor 2H 2 +O 2 → 2H 2 O Formula used: moles= given mass (g) molar mass Calculations: Calculate the moles of hydrogen and oxygen: Molar mass of H 2 = 2 . 0 g m o l Moles of H 2 = 1 .50 2 .0 =0 .75 moles Moles of O 1 = 12.0 32.0 = 0.375 moles Determination of Limiting reagent: As per balance chemical equation, ratio of moles of H 2 and O 2 is 2:1 Moles of H 2 react with O 2 = 2 × 0...

1st Edition

ISBN: 9780321834683

Author: Nivaldo J. Tro

Publisher: PEARSON

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Writing and Balancing Nuclear Equations

A nuclear equation is a symbolic representation of a nuclear reaction using certain symbols. It is studied in nuclear chemistry and nuclear physics.

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Chapter 1, Problem 45E

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The amount in grams of water vapor form.

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Chapter 1, Problem 44E

Chapter 1, Problem 46E

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The amount in grams of water vapor form.

Solution Summary: The author explains that the problem is based on moles and limiting reagent.

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To determine: The amount in grams of water vapor form.

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Chapter 1 Solutions

To determine:

The amount in grams of water vapor form.