Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 1, Problem 33Q
To determine
The age of the universe in seconds.
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I'm having trouble completing the problem I've attached a picture of below. I was able to find the the Earth's average speed in m/s relative to the sun by doing (2pi*(1.49x10^11))/31536000. But I am struggling to find the average velocity for the same thing over a period of one year in m/s. I was wondering how to calculate that? I've tried doing the (final velocity-initial velocity)/2 but the program doesn't accept my answer when using that approach.
A light year (LY) is the distance that light travels in one year.
1 LY = 9.46x1015 m.
Suppose we have detected a planet that orbits a star that is 104 light
years away. How many millions of years would it take us to get there if
we used a modern rocket with a maximum speed of 20.0 km/s (about
45,000 mph)? Assume 3 sig figs.
The value of Gme/re2, where me is the mass of the earth, re is the radius of the earth, and G is the universal gravitational constant is (enter your answer with three significant figures)
Chapter 1 Solutions
Universe: Stars And Galaxies
Ch. 1 - Prob. 1QCh. 1 - Prob. 2QCh. 1 - Prob. 3QCh. 1 - Prob. 4QCh. 1 - Prob. 5QCh. 1 - Prob. 6QCh. 1 - Prob. 7QCh. 1 - Prob. 8QCh. 1 - Prob. 9QCh. 1 - Prob. 10Q
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- (the complete question is in the picture) If the Newtonian constant has units G = [N · m2/kg2], the speed of light has units c = [m/s], the mass has units M = [kg] and the SI unit newtons is equivalentto N = [kg · m/s2], what are the units of the relation GM/c3?A. [kg · s]B. [kg · m2/s]C. [m2/s]D. [s]arrow_forwardIf there are 3x10^7 seconds in one year, a distance of one light year is equal to: 9 x 10^15 m 9 x 10^13 m 9 x 10^11 m O 9 x 10^9 marrow_forwardThe Earth is travelling around the sun at a speed of about 67,000 miles per hour [mph]. If it takes one year [yr] for the Earth to circle the Sun and we assume the Earth?s orbit is circular, what is the radius of the orbit in units of meters [m]? Use an appropriate SI prefix to report your answer so there are one, two, or three digits to the left of the decimal point.arrow_forward
- Convert 3,000 grades/century to Mega Hertz (MHz)arrow_forwardOxygen Atoms in People. Figure 5.7 shows that oxygen makes up about 65% of the mass of a human being. A single oxygen atom has a mass of 2.66 × 10−26 kg. (a) Use this fact to estimate the number of oxygen atoms in your body. (Hint: If you know your weight in pounds, you can convert to kilograms by dividing by 2.2.) (b) Compare your answer to the number of stars in the observable universe (which is roughly 1022).arrow_forward1 million kilometers can be expressed in scientific notation as: 10x10^6 km 10x10^-6 km none of these 1x10^6 km 1x10^-6kmarrow_forward
- Two exoplanets, UCF1.01 and UCF1.02 are found revolving around the same star. The period of planet UCF1.01 is 92.4 days, and that of planet UCF1.02 is 7.1 days. If the average distance of UCF1.01 to the sun is 5,828.0 km, what is the average distance of UCF1.02 to the sun in km? Please keep four digits after decimal points.arrow_forwardA light-year is the distance that light can travel in one year. Similarly, we can define a light-second, light-day, etc. as the distance that light can travel in other time intervals. Calculate the distance represented by each of the following: (Assume that the speed of light is 3 x 10^8m/s) 5 light-minutes 6 light-days 6 light-days, but this time answer in miles (enter just the number with no units)arrow_forwardUsing the data in the table below and the appropriate conversion factors, find the mean distance to the moon, in feet. Approximate Values of Some Measured Lengths Length (m) Distance from Earth to most remote known quasar 1 ✕ 1026 Distance from Earth to most remote known galaxies 4 ✕ 1025 Distance from Earth to nearest large galaxy (M31 in Andromeda) 2 ✕ 1022 Distance from Earth to nearest star (Proxima Centauri) 4 ✕ 1016 One lightyear 9 ✕ 1015 Mean orbit radius of the Earth about the Sun 2 ✕ 1011 Mean distance from the Earth to the Moon 4 ✕ 108 Mean radius of the Earth 6 ✕ 106 Typical altitude of a satellite orbiting Earth 2 ✕ 105 Length of a football field 9 ✕ 101 Length of a housefly 5 ✕ 10-3 Size of the smallest dust particles 1 ✕ 10-4 Size of the cells of most living organisms 1 ✕ 10-5 Diameter of a hydrogen atom 1 ✕ 10-10 Diameter of an atomic nucleus 1 ✕ 10-14 Diameter of a proton 1 ✕ 10-15arrow_forward
- One year on Mars is as long as 1.88 years on earth. How many seconds is a Martian year? Please give the correct answerarrow_forwardSuppose the Sun were somehow replaced by a star with five times as much mass. How long would the Earth year last in this last case? (hint: Newton’s version of Kepler’s 3rd Law)arrow_forwardSphere A has a mass of 3,450,818kg and sphere B had a mass of 293,183kg. If the magnitude of the gravitational force between the spheres is 6.8N, what is the distance between them to the second decimal place?arrow_forward
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