Chapter 1, Problem 27P

1.39 Make the following metric conversions:

(a)964 mLto L

(b)275 mm to cm

(c) 45.7 kg to g

(d) 475 cm to m

(e)21.64 cc to mL

(f) 3.29 L to cc

(g)0.044 L to mL

(h)711 g to kg

(1) 63.7 mL to cc

(j) 0.073 kg to mg

(k) 83.4 m to mm

(1) 361 mg to g

Interpretation Introduction

(a)

Interpretation:

The conversion of 96.4 mL to L should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Length can be converted from mL to L using the following conversion factor.

$\begin{array}{l}1\text{L =1000}\text{mL}\\ \frac{\text{1}\text{L}}{\text{1000}\text{mL}}\end{array}$.

Answer to Problem 27P

$\text{96}\text{.4}\text{mL}=0.0964\text{L}$.

Explanation of Solution

Converting 96.4 mL to L:

$\text{96}\text{.4}\text{mL×}\frac{\text{1}\text{L}}{\text{1000}\text{mL}}=0.0964\text{L}$.

Interpretation Introduction

(b)

Interpretation:

The conversion of 275 mm to cm should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Length can be converted from mm to cm using the following conversion factor.

$\begin{array}{l}1\text{cm}=1\text{0}\text{mm}\\ \frac{\text{1cm}}{\text{10}\text{mm}}\end{array}$.

Answer to Problem 27P

$\text{275}\text{mm}=27.5\text{cm}$.

Explanation of Solution

Converting 275 mm to cm,

$\text{275}\text{mm}\times \frac{\text{1cm}}{10\text{mm}}=27.5\text{cm}$.

Interpretation Introduction

(c)

Interpretation:

The conversion of 45.7 kg to g should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Mass can be converted from kg to g using the conversion factor,

$\begin{array}{l}\text{1}\text{kg =1000}\text{g}\\ \frac{\text{1000}\text{g}}{\text{1}\text{kg}}\end{array}$.

Answer to Problem 27P

$45.7\text{kg}=45,700g$.

Explanation of Solution

Converting 45.7 kg to g:

$45.7\text{kg}\times \frac{1000\text{g}}{\text{1}\text{kg}}=45,700g$.

Interpretation Introduction

(d)

Interpretation:

The conversion of 475 cm to m should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Length can be converted from cm to m using the following conversion factor.

$\begin{array}{l}\text{1}\text{m =100 cm}\\ \frac{\text{1}\text{m}}{\text{100}\text{cm}}\end{array}$.

Answer to Problem 27P

$\text{475 cm}=4.75\text{m}$.

Explanation of Solution

Converting 475 cm to m:

$\text{475 cm}\times \frac{\text{1}\text{m}}{\text{100}\text{cm}}=4.75\text{m}$.

Interpretation Introduction

(e)

Interpretation:

The conversion of 21.64 cc to mL should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Volume can be converted from cc to mL using the following conversion factor.

$\begin{array}{l}\text{1}\text{cc = 1mL}\\ \frac{1\text{mL}}{\text{1}\text{cc}}\end{array}$.

Answer to Problem 27P

$\text{21}\text{.6}\text{cc}=21.6\text{mL}$.

Explanation of Solution

Converting 21.6 cc to mL:

$\text{21}\text{.6}\text{cc}\times \frac{\text{1}\text{mL}}{\text{1}\text{cc}}=21.6\text{mL}$.

Interpretation Introduction

(f)

Interpretation:

The conversion of 3.29 L to cc should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Volume can be converted from L to cc using the following conversion factor.

$\begin{array}{l}\text{1}\text{L = 1000}\text{mL,}\text{1}\text{mL}\text{= 1cc}\\ \frac{\text{1000}\text{mL}}{\text{1}\text{L}}\text{\&}\frac{\text{1}\text{cc}}{\text{1}\text{mL}}\end{array}$.

Answer to Problem 27P

$\text{3}\text{.29 L}=3,290\text{cc}$.

Explanation of Solution

Converting 3.29 L to cc:

$\text{3}\text{.29 L}\times \frac{\text{1000}\text{mL}}{1\text{L}}\times \frac{\text{1}\text{cc}}{\text{1}\text{mL}}=3,290\text{cc}$.

Interpretation Introduction

(g)

Interpretation:

The conversion of 0.044 L to mL should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Volume can be converted using the following conversion factor.

$\begin{array}{l}1\text{L =1000}\text{mL}\\ \frac{\text{1000}\text{mL}}{\text{1 L}}\end{array}$.

Answer to Problem 27P

$\text{0}\text{.044 L}=44\text{mL}$.

Explanation of Solution

Converting 0.044 L to mL:

$\text{0}\text{.044 L×}\frac{\text{1000}\text{mL}}{\text{1 L}}=44\text{mL}$.

Interpretation Introduction

(h)

Interpretation:

The conversion of 711 g to kg should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Mass can be converted from g to kg using the following conversion factor.

$\begin{array}{l}\text{1}\text{kg = 1000}\text{g}\\ \frac{\text{1}\text{kg}}{\text{1000}\text{g}}\end{array}$.

Answer to Problem 27P

$\text{711}\text{g}=0.711\text{kg}$.

Explanation of Solution

Converting 711 g to kg:

$\text{711}\text{g}\times \frac{\text{1}\text{kg}}{\text{1000}\text{g}}=0.711\text{kg}$.

Interpretation Introduction

(i)

Interpretation:

The conversion of 63.7 mL to cc should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Volume can be converted from mL to cc using the following conversion factor.

$\begin{array}{l}\text{1}\text{mL = 1 cc}\\ \frac{\text{1 cc}}{\text{1}\text{mL}}\end{array}$.

Answer to Problem 27P

$\text{63}\text{.7}\text{mL}=63.7\text{cc}$.

Explanation of Solution

Converting 63.7 mL to cc:

$\text{63}\text{.7}\text{mL}\times \frac{1\text{cc}}{1\text{mL}}=63.7\text{cc}$.

Interpretation Introduction

(j)

Interpretation:

The conversion of 0.073 kg to mg should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Mass can be converted from kg to mg using the following conversion factor.

$\begin{array}{l}\text{1}\text{kg = 1000}\text{g,}\text{1}\text{g}\text{=}\text{1000}\text{mg}\\ \frac{\text{1000}\text{g}}{\text{1}\text{kg}}\text{\&}\frac{\text{1000}\text{mg}}{\text{1}\text{g}}\end{array}$.

Answer to Problem 27P

$0.073\text{kg}=73,000\text{mg}$.

Explanation of Solution

Converting 0.073 kg to mg:

$0.073\text{kg ×}\frac{\text{1000}\text{g}}{\text{1}\text{kg}}\text{ × }\frac{\text{1000}\text{mg}}{\text{1}\text{g}}=73,000\text{mg}$.

Interpretation Introduction

(k)

Interpretation:

The conversion of 83.4 m to mm should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Length can be converted from m to mm using the following conversion factor.

$\begin{array}{l}\text{1}\text{m =1000 mm}\\ \frac{\text{1000}\text{mm}}{\text{1 m}}\end{array}$.

Answer to Problem 27P

$\text{83}\text{.4 m}=83,400\text{mm}$.

Explanation of Solution

Converting 83.4 m to mm:

$\text{83}\text{.4 m}\times \frac{\text{1000}\text{mm}}{\text{1}\text{m}}=83,400\text{mm}$.

Interpretation Introduction

(i)

Interpretation:

The conversion of 361 mg to g should be determined.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Mass can be converted from mg to g using the conversion factor,

$\begin{array}{l}\text{1}\text{g =1000}\text{mg}\\ \frac{\text{1}\text{g}}{\text{1000}\text{mg}}\end{array}$.

Answer to Problem 27P

$\text{361 mg}=0.361g$.

Explanation of Solution

Converting 361 mg to g:

$\text{361 mg}\times \frac{1\text{g}}{\text{1000}\text{mg}}=0.361g$.